Please I need help. Answer with examples I am so confuzzled!

Mathematics

1 answer:

Marianna [84]4 years ago

4 0

Sorry not sure about this

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Five times the sum of a number and 27 ig greater than or equal to six times the sum of that number and 26 . What is the solution

harkovskaia [24]

Given

5(x + 27) ≥ 6(x + 26)

Find

The solution set of x

Solution

Eliminate parenthses.

... 5x + 135 ≥ 6x + 156

Subtract 5x+156

... -21 ≥ x

The solution set is all real numbers less than or equal to -21.

4 0

3 years ago

3<br><img src="https://tex.z-dn.net/?f=%203%5Cfrac%7B4%7D%7B5%7D%20%20%5Cdiv%20%203%5Cfrac%7B1%7D%7B6%7D%20" id="TexFormula1" ti

Jobisdone [24]

Hey There!

Here is your answer:

First write the equation down:

-3 4/5 ÷ -3 1/6

Then put the mixed fractions into whole numbers:

-3 4/5= 5×-3=-15+4=-11= -11/5
&
-3 1/6= 6×-3=-18+1=-17= -17/6

Now right the new problem:

-11/5×6/-17

Now multiply:

-11×6=-66
5×-17=-85

Which means -66/-85 is your answer!

Hope this helps!

3 0

3 years ago

(1) a) 5270 cl= ? dal

Ivanshal [37]

Answer:

Check below

Step-by-step explanation:

1) These metric volume units can be easily converted by dividing or multiplying by 10 and its multiple. Like this: each step up on the ladder multiply by 10. Each step down divide by 10

$a)5270 \:cl=527\:dl\\b)kl=5.3 \times 10=530 hl\\c)58000ml=5.8 dal =(\frac{58000}{10000})\\d)0.39 dal=3.9 l\\e)7.8 dal=780 dl\\f)57.2 ml=5.72 cl$ .

2) When it comes to area, the "ladder scheme" remains valid but now we'll multiply or divide by

$10^3$

Bear in mind these useful relations:

$1litre =\frac{1}{10^3}m^{3}$

$1 cm^{3} =1 ml$

$a) 3.7 l=3700 cm^{3}\\b)29.6 dm^{3}\\29.6 dm^{3} \rightarrow 29.6\times10^{3} cm^3=29.6\times10^{3} ml = 29.6\times10^{2} cl \:or\:2960 cl\\c)8.1l=8100 cm^{3}\\d)5l=\frac{5}{10^{-3}} m^{3}\\e)5.2 cl=52ml=52 cm^{3}=52\times10^{3}=52000 \:mm^{3}\\f)375 ml=375 cm^{3}\\g) 1300 cm^{3}=1300 ml=13 dl\\h) 8.6 ml= 8.6 cm^{3}\times\: 10^{3}=8600 mm^{3}\\i) 51.8\times 10^{11} l \rightarrow 51.8\times 10^{-11}km^{3}$