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tle=" 3\frac{4}{5} \div 3\frac{1}{6} " alt=" 3\frac{4}{5} \div 3\frac{1}{6} " align="absmiddle" class="latex-formula">
1 answer:
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9514 1404 393
Answer:
- y = 1/2x +2
- y = -2x +7
Step-by-step explanation:
The slope of a line is the tangent of the angle it makes with the x-axis. The given line has a slope of -1/3, so the lines we want will have slopes of ...
m1 = tan(arctan(-1/3) +45°) = 0.5 . . . . . using a calculator
m2 = tan(arctan(-1/3) -45°) = -2
Of course, these two lines are perpendicular to each other, so their slopes will have a product of -1: (0.5)(-2) = -1.
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We can use the point-slope form of the equation for a line to write the desired equations:
y = m(x -h) +k . . . . . line with slope m through point (h, k)
<u>Line 1</u>:
y = 1/2(x -2) +3
y = 1/2x +2
<u>Line 2</u>:
y = -2(x -2) +3
y = -2x +7
Answer:
Step-by-step explanation:
You have 3 unknowns: a, b, and c. It's our job to find them algebraically. I'm going to start with the point where x = 0 and y = 7. You'll see why in a minute. Filling in the standard form of a quadratic
using (0, 7):
gives you that c = 7. We will use that value now when we write the next 2 equations. Now the point (-2, 19):
and
so
12 = 4a - 2b
Now for the next point (-1, 12):
and
so
5 = a - b
Now we have a system of equations (the 2 bold font equations) that we will solve by elimination:
12 = 4a - 2b
5 = a - b
Multiply the bottom equation by -4 to get a new system:
12 = 4a - 2b
-20 = -4a + 4b
Add those together to get rid of the a terms and end up with
-8 = 2b so
b = -4
Now we can sub in -4 for b to solve for a. I'm using the second bold type equation to do this:
5 = a - (-4) and
5 = a + 4 so
a = 1 and the equation for the quadratic function is