Answer:
Step-by-step explanation:
You put 6. 2like this but in paper then make mult 6 x 9 then 8 x2 and then
8 9
add them up then multiply 8x9 then put the adding sum on top and the answer to 8 x9 on the bottom.
2 9
Answer:
Step-by-step explanation:
Rewrite this quadratic in standard form: 3x^2 + 7x - 1.
The coefficients of x are {3, 7, -1}, and so the discriminant is b^2 - 4ac, or
7^2 - 4(3)(-1), or 49 + 12, or 61. Because the discriminant is positive, this quadratic has two real, unequal roots
Answer:
8
Step-by-step explanation:
-3 + 6/n + 9
for n=3 is
-3 + 6/3 + 9
= -3 +2 + 9
= -1 + 9
= 8
Answer:
The pvalue of 0.0113 < 0.05 means that there is sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance
Step-by-step explanation:
The null hypothesis is:
![H_{0} = 28](https://tex.z-dn.net/?f=H_%7B0%7D%20%3D%2028)
The alternate hypotesis is:
![H_{1} < 28](https://tex.z-dn.net/?f=H_%7B1%7D%20%3C%2028)
The test statistic is:
![z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
In which X is the sample mean,
is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
A recent survey of 50 executives who were laid off during a recent recession revealed it took a mean of 26 weeks for them to find another position.
This means that ![n = 50, X = 26](https://tex.z-dn.net/?f=n%20%3D%2050%2C%20X%20%3D%2026)
Assume the population standard deviation is 6.2 weeks.
This means that ![\sigma = 6.2](https://tex.z-dn.net/?f=%5Csigma%20%3D%206.2)
Does the data provide sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance
We have to find the pvalue of Z, looking at the z-table, when
. It if is lower than 0.05, it provides evidence.
![z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%7D)
![z = \frac{26 - 28}{\frac{6.2}{\sqrt{50}}}](https://tex.z-dn.net/?f=z%20%3D%20%5Cfrac%7B26%20-%2028%7D%7B%5Cfrac%7B6.2%7D%7B%5Csqrt%7B50%7D%7D%7D)
![z = -2.28](https://tex.z-dn.net/?f=z%20%3D%20-2.28)
has a pvalue of 0.0113 < 0.05.
The pvalue of 0.0113 < 0.05 means that there is sufficient evidence to conclude that the mean time to find another position is less than 28 weeks at the 5% level of significance
False because for example using order of operation:
3-4*2= -5
But not using order of operation:
3-4*2=-1