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Black_prince [1.1K]
3 years ago
13

Which of the following approaches can be used to construct a parallelogram? Select one: a. Measure equal segments on parallel li

nes, then join the endpoints of these segments. b. Construct two congruent angles, then bisect them. c. Construct the perpendicular bisector of a segment, then bisect two of the right angles. d. Construct two perpendiculars to a parallel line.
Mathematics
1 answer:
Fittoniya [83]3 years ago
7 0
Please remember that a parallelogram is 4 parallel lines and the opposite sides are congruent. With that information you should be able to pick the correct answer.
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Evaluate the expression using an appropriate double angle formula.. cos^2(15) - sin^2(15)
riadik2000 [5.3K]
Cos²(15°) - sin²(15°) = cos(15° * 2) = √(3/2 so this is the answer by using apropriate formula  double angle identity
7 0
3 years ago
Combine like terms in the expression 4k + 2k - k + 3.<br> please help this is urgent
victus00 [196]

4k + 2k - k + 3

6k - 1k + 3

5k + 3

Answer: 5k + 3

3 0
2 years ago
Read 2 more answers
A long novel is opened to a random page; the probability that the page is numbered something between 21 and 31.
Harrizon [31]

Using the uniform distribution, considering that the novel has 435 pages, the probability that the page is numbered something between 21 and 31 is:

p = \frac{10}{435}

<h3>What is the uniform probability distribution?</h3>

It is a distribution with two bounds, a and b, in which each outcome is equally as likely.

The probability of finding a value between c and d is:

P(c \leq X \leq d) = \frac{d - c}{b - a}

Researching the problem on the internet, it is found that the novel has 435 pages, hence a = 0, b = 435, and the probability that the page is numbered something between 21 and 31 is given by:

P(21 \leq X \leq 31) = \frac{31 - 21}{435 - 0} = \frac{10}{435}

More can be learned about the uniform distribution at brainly.com/question/13889040

#SPJ1

5 0
2 years ago
4.5.36
Pavel [41]

Answer:

Step-by-step explanation:

Given function is h(t) = -16t² + 1500

a). For h(t) = 1000 feet,

   1000 = -16t² + 1500

   1000 - 1500 = -16t² + 1500 - 1500

   -500 = -16t²

    t² = \frac{500}{16}

    t = \sqrt{31.25}

    t = 5.59 sec

b). For h(t) = 940 feet,

   940 = -16t² + 1500

   940 - 1500 = -16t² + 1500 - 1500

   -16t² = -560

   t² = \frac{-560}{-16}

   t = \sqrt{35}

   t = 5.92 sec

c). For domain and range of the function,

  When the jumper comes down to the ground,

   h = 0

   0 =-16t² + 1500

   t² = \frac{1500}{16}

   t = \sqrt{93.75}

   t = 9.68 sec

  Since, x-values on the graph vary from x = 0 to x = 9.68,

  Domain : [0, 9.68]

  Vertex of the quadratic function: (0, 1500)

  Since, coefficient of the highest degree term is negative, parabola will open downwards.

  Therefore, y-values of the function will vary in the interval y = 0 to y = 1500

  Range: [0, 1500]  

3 0
3 years ago
Helpppppppppppppppppppppppppppppppp
erik [133]
-8 * 2 =  -16

answer
C. -16
4 0
3 years ago
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