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2 years ago

11

Teams of four are competing in a quarter-mile relay race. Each runner must run the same excavation distance. What is the distanc

e each teammate runs?

1 answer:

densk [106]2 years ago

7 0

Each teammate would run 330 feet because a quarter mile is 1320 feet and 1320/4=330

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Please answer now ASAP!! I have this assignment at school my teacher wants us to do but I don’t get it. Answer both questions wi

Tanzania [10]

Answer:

Step-by-step explanation:

1. If m<2 = 32°

the measure for m<4 is 148°

x + 32° = 180°

x = 148°

measure of m<6 = 148° alternate interior of m<4

2. If m<1 = 65°, then m<2 and m<3 are also 65°

Both m<2 and m<3 are vertical angles therefore they are 65°

m<1 and m<2 are corresponding angles therefore they are 65°

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2 years ago

In the year 2000, there were 5,000 people living in the town of Clairmont. By 2010, the population had grown to 5,600. What is t

kiruha [24]

I believe the answer is c ,BECAUSE... to find the change you take 5000 multiply it by the numbers that if aded would equal 5600 and 5000 times .12= 600, 5000 +600= 5600 hence the number of population in 2010.
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2 years ago

For five days Vicki recorded the temperature outside. The temperature (°F) was 36.9°, 34.6°, 37°, 40.2°, 32.8°. About what was t

storchak [24]

Answer:

C) 36

Step-by-step explanation:

You have to add all the numbers together and then divide by the amount of numbers, in your case 5.

5 0

2 years ago

Please find the surface area

nevsk [136]

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2 years ago

The daily cost of producing x high performance wheels for racing is given by the following function, where no more than 100 whe

algol [13]

Answer:

The production would be 25 wheels,

Lowest average cost is $ 123.75

Step-by-step explanation:

Given cost function,

$C(x) = 0.09x^3 - 4.5x^2 + 180x$

Where,

x = number of wheel,

So, the average cost per wheel,

$A(x) = \frac{C(x)}{x}=\frac{0.09x^3-4.5x^2 + 180x}{x}=0.09x^2 - 4.5x + 180$

Differentiating with respect to x,

$A'(x) = 0.18x - 4.5$

Again differentiating with respect to x,

$A''(x) = 0.18$

For maxima or minima,

$A'(x) = 0$

$0.18x - 4.5 = 0$

$0.18x = 4.5$

$\implies x = \frac{4.5}{0.18}=25$

For x = 25, A''(x) = positive,

i.e. A(x) is maximum at x = 25.

Hence, the production would be 25 wheels for the lowest average cost per wheel.

And, lowest average cost,

A(x) = 0.09(25)² - 4.5(25) + 180 = $ 123.75

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3 years ago