Answer:
(a) It costs $55 at Happy Fruiterer
(b) It will cost $49.64
(c) It is cheaper at Happy Fruiterer the second week
Step-by-step explanation:
Since Fruitz shop sells as 10% less than Happy Fruiterer at $50
10% more of $50 = 50 × 10/100 + 50
= $5 + $50 = $55
(a) n Kg of grapes will cost $55 at Happy Fruiterer
(b) if Happy Fruits discounts $55 by 5%, we will have
55 × 5/100 = 2.75
that is $55 - $2.75 = $52.25
If it is discounted further at 5% more the following week, we will have
$52.25 × 5/100 = $2.6125
≈ $2.61
Then the new price for the 2nd week is $52.25 - $2.61
= $49.64
(c) at the second wee of discounting, Fruitz shop still sells at $50 will Happy Fruiterer now see at $49.64. Therefore, it is cheaper at Happy Fruiterer
Begin by factoring 2 out of 2x^2 - 2x - 12 equals 0:
2(x^2 - x - 6) = 0
2(x - 3)(x + 2) = 0. 2 is never zero, but x-3 and x+2 can each be set = to 0:
This results in x = 3 and x = -2. The equation is true for these two x-values.
Combining like terms, we have
Answer:
95% confidence interval for the proportion of students supporting the fee increase is [0.767, 0.815]. Option C
Step-by-step explanation:
The confidence interval for a proportion is given as [p +/- margin of error (E)]
p is sample proportion = 870/1,100 = 0.791
n is sample size = 1,100
confidence level (C) = 95% = 0.95
significance level = 1 - C = 1 - 0.95 = 0.05 = 5%
critical value (z) at 5% significance level is 1.96.
E = z × sqrt[p(1-p) ÷ n] = 1.96 × sqrt[0.791(1-0.791) ÷ 1,100] = 1.96 × 0.0123 = 0.024
Lower limit of proportion = p - E = 0.791 - 0.024 = 0.767
Upper limit of proportion = p + E = 0.791 + 0.024 = 0.815
95% confidence interval for the proportion of students supporting the fee increase is between a lower limit of 0.767 and an upper limit of 0.815.
B 9.2 in will be your answer for the test
