All categories

3 years ago

Can someone answer this

Mathematics

1 answer:

ryzh [129]3 years ago

7 0

Answer:

y = 2x + b (the second answer choice)

Step-by-step explanation:

The slope-intercept form is y = mx + b (the m representing slope and the b representing y-intercept). Put the points in ratio form as a fraction and subtract the ratio with the smallest numbers from the ratio with the largest ratio (5/1 - 1/-1) to get 4/2. When simplified, it becomes 2/1, so the slope is 2. Using the slope found previously, subtract 1 from the x of (1, 5) and 2 from the y of (1, 5) to get the y-intercept. The resulting point is (0, 3), so the y-intercept is 3. Replace the m with the found slope (2) and b with the found y-intercept (3) to end up with y = 2x + 3.

You might be interested in

And this is the last one i need done

quester [9]

Answer:

x=-2.5,9

Step-by-step explanation:

Set them equal to each other to say 2x^2-9x=4x+45. Get them all on one side to get 2x^2-13x-45. Factor that out to get (x+2.5)(x-9). Set that equal to 0 to get x=-2.5,9

5 0

3 years ago

There are 158 students registered for American History classes. There are twice as many students registered in second period as

Margarita [4]

There are 28 students in first period and 56 students in sceond period and 74 students in third period

<em><u>Solution:</u></em>

Let the number of students in first period be "x"

Let the number of students in second period be "y"

Let the number of students in third period be "z"

<em><u>There are 158 students registered for American History classes.</u></em>

Therefore,

x + y + z = 158 ---------- eqn 1

<em><u>There are twice as many students registered in second period as first period</u></em>

number of students in second period = twice of number of students in first period

y = 2x ------- eqn 2

<em><u>There are 10 less than three times as many students in third period as in first period</u></em>

number of students in third period = 3 times number of students in first period - 10

z = 3x - 10 ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

x + 2x + 3x - 10 = 158

6x = 168

<em><u>Substitute x = 28 in eqn 2</u></em>

y = 2(28)

<em><u>Substitute x = 28 in eqn 3</u></em>

z = 3(28) - 10

z = 84 - 10

Thus there are 28 students in first period and 56 students in sceond period and 74 students in third period

5 0

3 years ago

Please help! Number 9) picture is included! Determine the base of the rectangle. (10 points) please help as soon as possible! :)

Juli2301 [7.4K]

The answer is 128m^2/8m equals 16m

3 0

3 years ago

If she can skip 300 feet in 20 seconds how far could she skip per second

elena55 [62]

300/20 = 15

she can skip 15 feet per second

hope this helps

5 0

3 years ago

Read 2 more answers

Salem High School's winter sports teams WON 72% of their games last season. If the teams played 50 games, how many games did the

Dmitriy789 [7]

Answer

Find out the how many games did the teams lose .

To prove

Formula

$Percentage = \frac{Part\ value\times 100}{Total\ values}$

As given

Salem High School's winter sports teams WON 72% of their games last season.

If the teams played 50 games .

Percentage = 72%

Total value = 50

Put in the formula

$72 = \frac{Number\ of\ games\ win\times 100}{50}$

$Number\ of\ games\ win = \frac{72\times 50}{100}$

Number of games win = 36

Number of games teams loses = Total number of games - number of games win

= 50 - 36

= 14

Therefore the number of games team loses are 14 .

5 0

4 years ago