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Elis [28]
3 years ago
10

A malware-infected networked host under the remote control of a hacker is commonly referred to as:

Computers and Technology
2 answers:
natali 33 [55]3 years ago
7 0

Answer:

Option a: Trojan

Explanation:

A Trojan or Trojan horse is one of the computer malware that exist in computing world. Trojan often appears as a legitimate software to deceive user to activate it by social engineering. Once the Trojan is activated in the user computer, a hacker can remote control the infected computer for malicious purposes such as removing files, sending files, displaying message or rebooting computer.

However, Trojan cannot be replicated in the infected computer.

nekit [7.7K]3 years ago
3 0

Answer:

Option C i.e., Bot is the correct option.

Explanation:

Because the bot is also a malware the infects the whole computer system and host's network by the hackers, using the remote control by which they remotely controlled the user's system without the permission of the user for the purpose of stealing the confidential data and the information from the computer system of the user they aimed.

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Write a C++ program to count even and odd numbers in array. The array size is 50. The array elements will be entered by the user
vlabodo [156]

Answer:

The program in C++ is as follows:

#include <iostream>

using namespace std;

int main(){

   int numbers[50];

   int evekount = 0, odkount = 0;

   for(int i = 0; i<50;i++){

       cin>>numbers[i];

       if(numbers[i]%2==0){            evekount++;        }

       else{            odkount++;        }

   }

   cout<<"Even Count: "<<evekount<<endl;

   cout<<"Odd Count: "<<odkount<<endl;

   return 0;

}

Explanation:

This declares the integer array of number

   int numbers[50];

This initializes the even count and odd count to 0

   int evekount = 0, odkount = 0;

This iterates from 1 to 50

   for(int i = 0; i<50;i++){

This gets input for the array

       cin>>numbers[i];

This checks for even

<em>        if(numbers[i]%2==0){            evekount++;        }</em>

This checks for odd

<em>        else{            odkount++;        }</em>

   }

This prints the even count

   cout<<"Even Count: "<<evekount<<endl;

This prints the odd count

   cout<<"Odd Count: "<<odkount<<endl;

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2 years ago
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3 years ago
Read 2 more answers
In Python please.
SOVA2 [1]

Answer:

negatives = []

zeros = []

positives = []

while True:

   number = input("Enter a number: ")

   if number == "":

       break

   else:

       number = int(number)

       if number < 0:

           negatives.append(number)

       elif number == 0:

           zeros.append(number)

       else:

           positives.append(number)

for n in negatives:

   print(n)

for z in zeros:

   print(z)

for p in positives:

   print(p)

Explanation:

Initialize three lists to hold the numbers

Create a while loop that iterates until the user enters a blank line

Inside the loop:

If the number is smaller than 0, put it in the negatives list

If the number is 0, put it in the zeros list

Otherwise, put the number in the negatives list

When the while loop is done, create three for loops to print the numbers inside the lists

5 0
2 years ago
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