For the answer to the question above,
<span>g(f(x)) = (4x^2 + x + 1)^2 - 2 </span>
<span>g(f(x)) = (16x^4 + 4x^3 + 4x^2 + 4x^3 + x^2 + x + 4x^2 + x + 1) - 2 </span>
<span>g(f(x)) = 16x^2 + 8x^3 + 9x^2 + 2x + 1 - 2 </span>
<span>g(f(x)) = 16x^2 + 8x^3 + 9x^2 + 2x - 1
I hope my answer helped you. Feel free to ask more questions. Have a nice day!</span>
Answer:
Step-by-step explanation:
Given tq equation of the height reached by the rocket as y=-16x^2+235x+133
The velocity of the object at its maximum height is zero
v = dy/dx = 0(at max height)
v =-32x +235
0 =-32x+235
x = 235/32
x = 7.34
Hence the rocket will reach its maximum height after 7.34seconds
I’m tryna look for that too
6 2/3 i hope this helped you c:
Answer:
Step-by-step explanation:
Given
Required
Find x
The area is calculated as thus:
Substitute values
Multiply through by 2
Remove absolute sign
Add 6 to both sides
Divide by 3
<em>So, the coordinates are (-8, 11) or (12,11)</em>
