Answer:
3.4, 2.1, -1.2, -3.4, -7.1
Step-by-step explanation:
You would start from the positives and work down.
<u>√(a^6b³)</u> = <u> a³√b³ </u><u /> = <u>a³√b³</u> = <u>a³√b³</u>
98 √(49 × 2) √49√2 7√2
First number = x
Consecutive number = x+1
"squares differ by 31" means to square both numbers and subtract them:
(x+1)^2 - (x)^2 = 31
x^2+2x+1 - x^2 = 31
2x+1 = 31
2x = 30
x = 15 (first number)
x+1 = 15+1 = 16 (consecutive number)
Answer:
Options are attached.
The minimum of 3 is represented by the lower extreme of line, the maximum of 24 is represented by the higher extreme of the line. However, you can observe that all options have these minimum and maximum.
Now, if the median is 15, the middle line of the rectangle must be placed in that number. If the lower quartile is 6, that means the left side of the rectangle must be placed in that number, and if the upper quartile is 19, that means the right side of the rectangle must be placed in that number.
So, we have to look for a box plot, which rectangle begins at 6 and ends at 19. As you can observe such box plot is not listed. Therefore, the answer is none of the above.