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joja [24]
3 years ago
10

Adapting and using formulas

Mathematics
1 answer:
Savatey [412]3 years ago
7 0
Ohhh it might be...

R = d/t
tr = d
/r    /r
t = d/r

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Find the slope of this line. *
Elden [556K]

Answer:

1

Step-by-step explanation:

Slope = y2 - y1 / x2 - x1 so, (0 - (-2)) / (1 - (-1)) == 2/2 = 1

3 0
3 years ago
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What is 2 3/4 divided by 7
alisha [4.7K]
2 3/4 divided by 7=0.39285714285
7 0
4 years ago
In - ABC shown below, side AC is extended to point D with mZ DAB = (180 – 3x) °,
Setler [38]

Answer:

<BAC = 36degrees

Step-by-step explanation:

Find the diagram attached

The sum of the interior angle is equal to the exterior. Hence;

<B + <C = <DAB

6x+40 + x+20 = 180 - 3x

7x+60 = 180 - 3x

7x+3x = 180 - 60

10x = 120

x = 120/10

x = 12

Get <BAC

<BAC = 180 - (180-3x)

<BAC = 180-180+3x

<BAC = 3x

<BAC = 3(12)

<BAC = 36degrees

4 0
3 years ago
If you flip a fair coin 4 times, what is the probability that you will get exactly 2 tails?
andreyandreev [35.5K]

Answer:

50/50

Step-by-step explanation:

2 is half of 4. 4/2 is 50/50

3 0
3 years ago
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Find the Horizontal Tangent for x^3/3+3x^2-16x+9
bazaltina [42]

Answer:

The two horiz. tang. lines here are y = -3 and y = 192.

Step-by-step explanation:

Remember that the slope of a tangent line to the graph of a function is given by the derivative of that function.  Thus, we find f '(x):

f '(x) = x^2 + 6x - 16.  This is the formula for the slope.  We set this = to 0 and determine for which x values the tangent line is horizontal:

f '(x) = x^2 + 6x - 16 = 0.  Use the quadratic formula to determine the roots here:  a = 1; b = 6 and c = -16:  the discriminant is b^2-4ac, or 36-4(1)(-16), which has the value 100; thus, the roots are:

      -6 plus or minus √100

x = ----------------------------------- = 2 and -8.

                         2

Evaluating y = x^3/3+3x^2-16x+9 at x = 2 results in y = -3.  So one point of tangency is (2, -3).  Remembering that the tangent lines in this problem are horizontal, we need only the y-coefficient of (2, -3) to represent this first tangent line:  it is y = -3.

Similarly, find the y-coeff. of the other tangent line, which is tangent to the curve at x = -8.  The value of x^3/3+3x^2-16x+9 at x = -8 is  192, and so the equation of the 2nd tangent line is y=192 (the slope is zero).


3 0
3 years ago
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