Question

Select the correct answer from each drop-down menu.

Answer 1

Answer:

The probability of the spinner landing on an even number or a multiple of 3 is 0.6667 .

The probability of the spinner landing on an odd number or a number between 4 and 15 (both numbers excluded) is 0.7778 .

Step-by-step explanation:

Be the events

A = even number

B = Multiple of 3

C = Odd Number

D = Number between 4 and 15, both numbers excluded

The sets are as follows:

A = {2,4,6,8,10,12,14,16,18}

B = {3,6,9,12,15,18}

C = {1,3,5,7,9,11,13,15,17}

D = {5,6,7,8,9,10,11,12,13,14}

To calculate the probability that the roulette lands in an even number or in a multiple of 3, we make the union of A and B:

A U B = {2,3,4,6,8,9,10,12,14,15,16,18} = 12 numbers of 18

P (A U B) = 12/18 = 2/3 = 0.6667

To calculate the probability that roulette lands on an odd number or a number between 4 and 15 (both numbers excluded), we make the union of C and D:

C U D = {1,3,5,6,7,8,9,10,11,12,13,14,15,17} = 14 numbers of 18

P (C U D) = 14/18 = 7/9 = 0.7778

The first answer is 0.6667

The second answer is 0.7778

Hope this helps!