Answer:
more than likely none
Step-by-step explanation:
because the is no number higher than 8 that can go into 8 evenley
Answer:
a = 60°
60°, 60°, 120°, and 120°.
Step-by-step explanation:
Sum of interior angles of a quadrilateral = 360°
Therefore:
a° + a° + 2a° + 2a° = 360°
Add like terms
6a = 360
Divide both sides by 6
a = 60
2a = 2(60) = 120°.
Angle measure from least to greatest are 60°, 60°, 120°, and 120°.
Let, coordinate of point A' is (x,y).
Since, A' is the symmetric point A(3, 2) with respect to the line 2x + y - 12 = 0.
So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.
Now, their center is given by :

Also, product of slope will be -1 .( Since, they are parallel )

x = 2y - 1
So, 
Also, C satisfy given line :

Also,

Therefore, the symmetric points is
.
<u><em>16.1 is the final answer. </em></u>
<em>Product- it's going to be multiply by the numbers only.</em>

<em>You can also round up to the nearest tenths is 16.0</em>
<em>Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie</em>
Answer:
x ≈ ±20.086/√(t - 1)
Step-by-step explanation:
ln(t - 1) + ln(x²) = 6
Recall that lnu + lnv = ln(uv). Then
ln(t - 1) + ln(x²) = ln[(t-1)x²] = 6
Take the natural antilogarithm of each side
(t - 1)x² = e⁶
Divide each side by t - 1
x² = e⁶/(t-1)
Take the square root of each side
x = ±e³/√(t - 1)
x ≈ ±20.086/√(t - 1)