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Vilka [71]
3 years ago
10

height of the gateway arch shown on the Missouri quarter is 630 feet or 7,560 inches. find how many 4-inch stacks of quarters ma

ke up the gateway arch. if there are 58 quarters in a 4-inch stack, how many quarters high is the arch?
Mathematics
2 answers:
Bingel [31]3 years ago
8 0
<span>The height of Gateway Arch shown on the Missouri quarter is 630 feet or 7,560 inches. Find how many 4 inch stacks of quarters make up the height of the Gateway Arch. If there are 58 quarter in 4 inch stack o, how many quarters high is the arch? </span>

<span>Hence to find how many 4 inch stacks of quarters make up the height of the </span><span>Gateway Arch, 

Since the Gateway Arch is 7560 then for every stack is 4 inches to find the stacks all in all, we just have to divide 7560 / 4 = 1890

Then, to find </span><span>how many quarters high is the arch, 
58 quarter x 4 inch = 232 quarters high in inches.
</span>
11111nata11111 [884]3 years ago
4 0

Answer:

The height of the Gateway arch shown on the Missouri quarters 630 feet, or 7560 inches. Find how many 4-inch stacks of quarter make up the height of the gateway arch. If there are 58 quarters in a 4 inch stack, how many quarters high is the arch?

 

7,560 / 4 =1,890 number of 4-inch stacks of quarters,

1,890 x 58=109,620 number of quarters that will equal the height of the Gateway Arch.

Step-by-step explanation:

You might be interested in
Taji has a total of 98 quarters and dimes. their value is $18.20 how many quarters does taji have?
scZoUnD [109]

Answer:

Taji has a total of 56 quarters.

Step-by-step explanation:

Let <em>x</em> be the number of quarters that Taji has.

Amount in terms of quarter =0.25 \times x

Let <em>y</em> be the number of dimes that Taji has.

Amount in terms of quarter =0.10 \times y

As per question statement:

x + y = 98 ...... (1)

Total amount is $18.20 as given in the question statement.

\Rightarrow 18.20 = 0.25 \times x + 0.10 \times y\\\Rightarrow 25x + 10y = 1820 ...... (2)

Solving equations (1) and (2):

Multiplying equation (1) by 10 and subtracting from equation (2):

25x + 10y -10x -10y= 1820 - 980\\\Rightarrow 15x = 840\\\Rightarrow x = 56

<em>x </em>is the number of quarters that Taji has.

So, Taji has a total of 56 quarters.

4 0
3 years ago
A bag contains green tokens and black tokens. There are 8 green tokens in the bag. The ratio of green tokens to black tokens is
melomori [17]

Answer: 2 tokens.

Step-by-step explanation:

From the question, we are informed that a bag contains green tokens and black tokens and that there are 8 green tokens in the bag.

We are further told that the ratio of green tokens to black tokens is 4 for every 1.

Since the green tokens is 4× the black tokens, therefore the number of black tokens in the bag will be:

= 8/4

= 2 tokens

3 0
3 years ago
Find the value of sin H rounded to the nearest hundredth, if necessary
Soloha48 [4]

Answer:

7/25 or .28

Step-by-step explanation:

sin=opp/hyp

7/25

8 0
3 years ago
Kala’s company makes solid metal balls for various industrial uses. A customer wants aluminum balls that have a diameter of 6 in
KiRa [710]

7,912.8 inch³ of aluminum is needed to make 70 metal balls.

Step-by-step explanation:

Step 1:

The area of a sphere is calculated by multiplying \frac{4}{3} with π and the cube of the radius (r³).

In the given problem, the diameter is 6 inches. So the radius of the spheres is 3 inches.

The volume of a sphere,V = \frac{4}{3} \pi r^{3} .

So if r = 3 inches and π = 3.14,  

V = \frac{4}{3} (3.14) (3^{3})  = 113.04 cubic inches.

So for a single aluminum ball, 113.04 inch³ of aluminum is needed.

Step 2:

If 113.04 inch³ of aluminum is used for 1 ball, then we multiply 70 with this value to determine the aluminum needed for 70 such balls.

The aluminum needed for 70 metal balls = 70(113.04) = 7,912.8 inch³.

So 7,912.8 inch³ of aluminum is needed to make 70 metal balls.

7 0
4 years ago
Please help me!!!<br> it would be greatly appreciated
HACTEHA [7]

Answer:

11.72

Step-by-step explanation:

6.76 + 4.96 = 11.72

7 0
2 years ago
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