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Mashutka [201]
3 years ago
9

PLEASE HELP ME!!!

Mathematics
2 answers:
wlad13 [49]3 years ago
3 0
It could be C or D but a salary is a fixed payment that is USUALLY on a yearly payment. I would answer D
coldgirl [10]3 years ago
3 0

Payment of a certain amount paid for the whole yea

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What is the slope of this graph?<br><br> −1/3<br><br> 3<br><br> 1/3<br><br> −3
FromTheMoon [43]
I'm assuming there is probably a graph that goes with this problem so here is all the info I can give you with the four choices: If it is -1/3, the line will go DOWN 1, over 3 (just count on the graph) If it is 3, the line will go UP 3, over 1 If it is 1/3, the line will go UP 1, over 3 And if it it -3, it will go DOWN 3, over 1 (If the slope is 3 or -3, it would be quite steep compared to a slope of 1/3 or -1/3) Hope that helps!
4 0
3 years ago
I need help wt this pls do it asap
viktelen [127]

Answer:

7/4

Step-by-step explanation:

its d because 4/7 =7/4

6 0
3 years ago
In parallelogram abcd, ab=14, bc=20, m(angle)b=54. Find to the nearest tenth the length of diagonal bd, and find measure angle d
muminat
It is is a parallelogram, hence we have to face sides equal in length and the opposite angles are also the same. From the given above we have:
ab=14 and its opposite side cd=14
bc=20 and its opposite side da=20

Solving for the diagonal measurement bd, we have consecutive angles are equal to 180°
∠A+∠B=180°
∠A=180°-54°
∠A=126° , ∠B=54° ,∠C=126° and ∠D=54°
bd²=ab²+da²-2(ab)(da)cos126°
bd²=14²+20²-2*14*20cos126°
bd=30.42 unit

Solving for the angle dbc, we have
cos dbc=bc²+bd²-cd²/a*bc*bd
cos dbc=20²+30.42²-14²/2*20*30.42
dbc=21.76° 
3 0
3 years ago
What is the answer to:<br> 18 - 5z + 6z &gt; 3 + 6
miv72 [106K]
18 - 5z + 6z > 3 + 6
18 + z > 9
-18        -18
z > -9
3 0
3 years ago
Express with radical signs instead of fractional exponents. Rationalize the denominator.
CaHeK987 [17]

x^{\frac{1}{2}} = \sqrt[2]{x} and 3^{-\frac{1}{2}} = \frac{1}{3^{\frac{1}{2}} } = \frac{1}{\sqrt[2]{3}} so

3^{-\frac{1}{2}} x^{\frac{1}{2}} = \frac{1}{\sqrt{3}} \cdot \sqrt{x}  = \frac{\sqrt{x}}{\sqrt{3}}

and you rationalize denominator by multiplying numerator and denominatr by \sqrt{3} so that gives--

\frac{\sqrt{x}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3x}}{3}

Your answer is \frac{\sqrt{3x}}{3}

5 0
3 years ago
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