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ra1l [238]
3 years ago
9

The male and female guests attending Patricia's party were surveyed to see if they drove to the party or did not drive. The data

is displayed in the table below: Male Female Drove to the party 26 24 Did not drive to the party 34 116 If a guest is chosen at random from this group, what are the chances of choosing a guest who is male and did not drive to the party?

French
2 answers:
ElenaW [278]3 years ago
5 0
Gotcha covered.

The question asks for a random guest chosen randomly; so we know that there are a total of 200 guests. I got 200 by adding both male and female drivers and non-drivers.

Specifically, the question asks for male non-drivers. There are 34 male non-drivers out of 200 total guests.

Picking a male non-driver out of total guests results in this fraction: 34/200

We can simplify this fraction by dividing both sides by 2 since it can divide both numbers.

Once we do that, we get 17/100.

A percent is a number out of 100 and we know that number. It's 17, so we can say there's 17% a male non-driver would be picked out of the guests.

Hope this helped. If you have any questions, leave a comment. Good luck!
goldfiish [28.3K]3 years ago
3 0

Answer:

17%

Explanation:

Step 1 :

34 is the amount of men who didnt drive to the party

200 is the total amount of people surveyed

use the formula P(event) = \frac{outcomes }{total }

P(male and did not drive to the party) = 34/200=

17%

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