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Tems11 [23]
2 years ago
13

A pet store sells puppies and kittens in the ratio 5 : 4 . If their sales of puppies and kittens combined came to 27, how many p

uppies did they sell?
Mathematics
2 answers:
Anika [276]2 years ago
4 0

Answer:

15 puppies

Step-by-step explanation:

A pet store sells puppies and kittens in the ratio 5 : 4

As per the ratio, total puppies and kittens is 5+4= 9

If their sales of puppies and kittens combined came to 27

The ratio of puppies to the total is 5:9

LEt x be the puppies sold

RAtio of puppies sold to the total is x: 27

Now make a proportion using the ratio and solve for x

\frac{5}{9} =\frac{x}{27}

cross multiply it

135=9x

Divide both sides by 9

x=15

S, 15 puppies

dimulka [17.4K]2 years ago
3 0
So puppies will be 5x and Kittens 4 x so they combined will be 5x+4x=27
9x=27
X=3
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3 years ago
The number of requests for assistance received by a towing service is a Poisson process with rate θ = 4 per hour.a. Compute the
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Answer:

a) 9.93% probability that exactly ten requests are received during a particular 2-hour period

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c) 2

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

Poisson process with rate θ = 4 per hour.

This means that \mu = 4n, in which n is the number of hours.

a. Compute the probability that exactly ten requests are received during a particular 2-hour period.

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This is P(X = 10). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 10) = \frac{e^{-8}*8^{10}}{(10)!} = 0.0993

9.93% probability that exactly ten requests are received during a particular 2-hour period

b. If the operators of the towing service take a 30-min break for lunch, what is the probability that they do not miss any calls for assistance?

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This is P(X = 0). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

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c. How many calls would you expect during their break?

n = 0.5, so \mu = 4*0.5 = 2

4 0
3 years ago
The difference of two numbers.(a,b) is 21. The difference of 5 times a and 2 times b is 18. What are the values of a,b?
ziro4ka [17]
The equation is b-a= 21;
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therefore 29-8= 21
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Your list does not include any advantages
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Elimination using addition and subtraction. <br> -4x+4y=-20<br> -2x+4y=-2
goldfiish [28.3K]

I would subtract the 2nd from the first one

so -4x - -2x = -2x

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4y =16

y = 4



3 0
3 years ago
Read 2 more answers
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