Determine the solution of the system. Show your work. Y = 5x – 9 Y = 2x + 6
2 answers:
The solution is (x, y) = (5, 16). My "work" is to make use of a graphing calculator.
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You can subtract the second equation from the first. This gives
... 0 = 3x -15
Then, divide by 3 and add 5.
... 0 = x - 5
... 5 = x
Substitute this value into either equation to find y.
... y = 2x +6
... y = 2·5 +6
... y = 16
The strategy to subtract the second equation from the first is based on the observation that both equations give expressions for y, and the x-coefficient in the first equation is the larger of the two x-coefficients. Thus, the subtraction we chose will eliminate y and give an x-term with a positive coefficient.
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Answer:
Step-by-step explanation:
The expression can be simplified by applying the a properties of exponents, specifically the Product of powers, which states that:
Where b is the base and a and c are exponents.
Then simplify it by rewriting the base () and adding the exponents of the expression (8 and 9).
You will get the expression simplified and written as a power:
Answer:
Step-by-step explanation:
Hello!
<em>The table shows the daily sales (in $1000) of shopping mall for some randomly selected days </em>
<em>Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5 </em>
<em>Days 18 27 31 40 56 55 23 </em>
<em>Use it to answer questions 13 and 14. </em>
<em>13. What is the approximate value for the modal daily sales? </em>
To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)
The modal interval is [3.1-3.5]
Now using the following formula you can calculate the Mode:
Li= Lower limit of the modal interval.
c= amplitude of modal interval.
fmax: absolute frequency of modal interval.
fprev: absolute frequency of the previous interval to the modal interval.
fpost: absolute frequency of the posterior interval to the modal interval.
<em>A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53 </em>
Of all options the closest one to the estimated mode is A.
<em>14. The approximate median daily sales is … </em>
To calculate the median you have to identify its position first:
For even samples: PosMe= n/2= 250/2= 125
Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.
F(1)= 18
F(2)= 18+27= 45
F(3)= 45 + 31= 76
F(4)= 76 + 40= 116
F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]
Li: Lower limit of the median interval.
c: Amplitude of the interval
PosMe: position of the median
F(i-1)= accumulated absolute frequency until the previous interval
fi= simple absolute frequency of the median interval.
<em>A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664</em>
Of all options the closest one to the estimated mode is C.