1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lelechka [254]
3 years ago
5

Location is knownLocation is known to affect the number, of a particular item, sold by an automobile dealer. Two different locat

ions, A and B, are selected on an experimental basis. Location A was observed for 18 days and location B was observed for 13 days. The number of the particular items sold per day was recorded for each location. On average, location A sold 39 of these items with a sample standard deviation of 8 and location B sold 49 of these items with a sample standard deviation of 4. Does the data provide sufficient evidence to conclude that the true mean number of sales at location A is fewer than the true mean number of sales at location B at the 0.01 level of significance
Mathematics
1 answer:
KIM [24]3 years ago
3 0

Answer:

There is  enough evidence to support the claim that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

Then, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2> 0

Being μ1: true mean number of sales for Location A and μ2: true mean number of sales for Location B.

The significance level is 0.01.

The sample 1 has a size n1=18 and the sample 2 has a size n2=13.

The sample 1 has a mean of 39 and a standard deviation of 8.

The sample 2 has a mean of 49 and a standard deviation of 4.

The difference between sample means is Md=-10.

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{8^2}{18}+\dfrac{4^2}{13}}\\\\\\s_{M_d}=\sqrt{3.556+1.231}=\sqrt{4.786}=2.188

Then, we can calculate the t-statistic as:

The degrees of freedom for this test are:

This test is a left-tailed test, with 29 degrees of freedom and t=-4.571, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.00004) is smaller than the significance level (0.01), the effect is significant.

The null hypothesis is rejected.

There is  enough evidence to support the claim that the true mean number of sales at location A is fewer than the true mean number of sales at location B.

You might be interested in
If the relationship is proportional, what is the missing value from the table? x y –3 –1 –12 ? –30 –10 –8 –6 –5 –4
Ann [662]

Answer:

-4

Step-by-step explanation:

I got it wrong and it showed me the answer.

7 0
3 years ago
Read 2 more answers
The length of a rectangular plot of land is 10 yards more than its width. If the area of the land 600 square yards , find the di
vagabundo [1.1K]
<span>Let the width of the rectangular plot of land be 'x' yards. Given that the length of the rectangular plot of land is 10 yards more than its width. So, width of the rectangular plot of land = (x + 10) yards. Also given that the area of the rectangular plot of land is 600 square yards. We know that, area of a rectangle = length * width That is, (x+10) * x = 600 x^2 + 10x = 600 x^2 + 10x - 600 = 0 x^2 + 30x - 20x -600 = 0 x(x + 30) - 20(x + 30) = 0 (x +30)(x -20) =0 Therefore, either (x + 30) = 0 or (x - 20) = 0 If x + 30 = 0, then x = -30 and If x - 20 = 0, then x = 20 Since 'x' represents the width of a rectangular plot of land it cannot be negative. Therefore, width of the rectangular plot of land = 20 yards length of the rectangular plot of land= x + 10 = 30 yards</span>
5 0
3 years ago
Find two natural numbers that are multiples of both 12 and 15​
Diano4ka-milaya [45]

Answer:

60 and 120

Step-by-step explanation:

The LCM of 12 and 15 is 60

The smallest natural number that would be a multiple of 12 and 15 would be 60.

To find the second number, all you do is multiply 60 by 2 and you get 120.

(60 * 2 = 120)

8 0
2 years ago
Read 2 more answers
WILL MARK BRAINLIEST!
Dennis_Churaev [7]

Answer: A

Step-by-step explanation: Took the test |

                                                                     \/

4 0
3 years ago
Solve the equation P=KTV for the letter K.
ddd [48]

Answer:

K = \frac{P}{TV}

Step-by-step explanation:

P = KTV

Divide both sides by TV

(P/TV) = K

5 0
2 years ago
Other questions:
  • Luisa has 12 playing cards.she place 2 out of every 3 cards face up
    7·1 answer
  • Anybody have an answer?
    10·1 answer
  • Why is this so hard ?? :(
    14·2 answers
  • To the nearest square unit, what is the area of the regular heptagon shown below?
    10·2 answers
  • How do you solve x for (x+5)^3/2 = ( x-1)^3
    11·2 answers
  • The table below shows the account balances for four different customer accounts at the City
    14·2 answers
  • F(x) = (x + 3)(x + 5).
    7·2 answers
  • 64 of 80<br>Express as percentage​
    14·2 answers
  • Find the slope of the line that passes through (10, 10) and (5,14)
    5·1 answer
  • Classify the polynomial by its name: 3
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!