Answer:
1008
Step-by-step explanation:
geometric sequence:
a=16
r=32/16=2
Sum of GS:
s=a(1-r^n)/(1-r)
S(6)=16(1-2^6)/(1-2)
=1008
Answer:
The second answer option
Step-by-step explanation:
Lmk if you need explanation
Answer:
1/2
Step-by-step explanation:
Hi!
To compare this two sets of data, you need to use a t-student test:
You have the following data:
-Monday n1=16; <span>x̄1=59,4 mph; s1=3,7 mph
-Wednesday n2=20; </span>x̄2=56,3 mph; s2=4,4 mph
You need to calculate the statistical t, and compare it with the value from tables. If the value you obtained is bigger than the tabulated one, there is a statistically significant difference between the two samples.

To calculate the degrees of freedom you need to use the following equation:

≈34
The tabulated value at 0,05 level (using two-tails, as the distribution is normal) is 2,03. https://www.danielsoper.com/statcalc/calculator.aspx?id=10
So, as the calculated value is higher than the critical tabulated one,
we can conclude that the average speed for all vehicles was higher on Monday than on Wednesday.
Take the coordinates
Ex.
(-5,-1) and count it on the chart
The first number is your x value and ur second number is ur y
Y= up and down
X= side to side