A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function
h = –16t2 + 36t + 9. a. In how many seconds does the ball reach its maximum height? Round to the nearest hundredth if necessary. b. What is the ball’s maximum height
<span>We know that the height h in feet of the ball after t seconds is given by the function h=-16t^2+36t+9. f(x)=ax^2+bx+c From the function we know that the graph is a parabola and </span><span>because of the negative lead coefficient we know that the parabola is opening down. a.x=-b/2a=-36/(-32)=36/32=1.125 In 1.125 seconds the ball will reach its maximum height. b. The maximum height is: f(1.125)</span>