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4 years ago

3p - 5 = 19 Answer when solved??

Mathematics

1 answer:

lianna [129]4 years ago

3 0

Answer: P=8

Step-by-step explanation:

3p-5=19

U turn -5 to +5

Then u add 5 to both sides, -5 and 19

3p-5=19

+5=+5

-5 and +5 cancel each other out so know it’s

3p=24

Because 19 plus 5 is 24

Now u have to get the variable by itself by dividing 3 on both sides of the equal sign 3p and 24

3 and 3 cancel each other out so now you only have p=24 but then 24 divided 3 is 8

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Water flowed out of a tank at a steady rate. A total of 18 1/2 gallons flowed out of the tank in 4 1/4 hours. Which expression

Alecsey [184]

Answer:

In 1 hour water flowed out = $\frac{74}{17}$ gallons

Step-by-step explanation:

Given as ,

The quantity of water flowed out of tank = 18 $\frac{1}{2}$ gallons

= $\frac{37}{2}$ gallons

The time spend in flowing water out of tank = 4 $\frac{1}{4}$ hours

= $\frac{17}{4}$ hours

∵ In $\frac{17}{4}$ hours , water flowed out = $\frac{37}{2}$

∴ In 1 hours , water flowed out = $\frac{37\times4} {17\times2}$

So, in 1 hour water flowed out = $\frac{74}{17}$ gallons Answer

6 0

3 years ago

Read 2 more answers

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Sauron [17]

Answer:

$g(-2)=8$

Step-by-step explanation:

We just need to evaluate the function at -2.

The function is:

$g(x)=x^{2}-2x$

Therefore, g(-2) will be:

$g(-2)=(-2)^{2}-2(-2)$

$g(-2)=4+4$

$g(-2)=8$

I hope it helps you!

7 0

3 years ago

usally ellis rides his bycecle 5 4/5 miles a day. today he rode half his usual distance how far did he ride

Tcecarenko [31]

Answer:

2.9

Step-by-step explanation:

Because you divide 5 4/5 by 2 and get 2.9

4 0

4 years ago

I need help with this problem. Given: BC = 10 inches AC = √50 inches m∠CBD = 60° m∠CAD = 90° Calculate the exact area of the sha

Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

Area of a sector = $\frac{\theta}{360}(\pi r^{2})$

Where θ = Central angle subtended by an arc

r = radius of the circle

Area of the sector BCD = $\frac{60}{360}(\pi) (10^{2})$

= 52.36 in²

Area of equilateral triangle BCD = $\frac{\sqrt{3} }{4}(\text{Side})^2$

= $\frac{\sqrt{3} }{4}(10)^2$

= $25\sqrt{3}$ in²

= 43.30 in²

Area of the shaded portion in ΔBCD = 52.36 - 43.3

= 9.06 in²

Area of sector CAD = $\frac{90}{360}(\pi)(\sqrt{50})^2$

= 39.27 in²

Area of right triangle CAD = $\frac{1}{2}(\text{Base})(\text{Height})$

= $\frac{1}{2}(\text{AC})(\text{AD})$

= $\frac{1}{2}(\sqrt{50})(\sqrt{50})$

= 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

= 14.27 in²

Area of the shaded part of the figure = 9.06 + 14.27

= 23.33 in²

8 0

3 years ago

On a map of Ayana’s town, the library is located at (-5,-3) and the middle school is located at (0,2).

Anna [14]

Answer:

Yes, It would only 20 minutes because it is only 4 miles.

Step-by-step explanation:

Starting at the middle school, it would take 20 minutes on her bike.

6 0

3 years ago