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Sindrei [870]
3 years ago
8

Multiply 3.76 X.2 Show your work

Mathematics
1 answer:
WITCHER [35]3 years ago
7 0

Answer:

7.52

Step-by-step explanation:

  1. Write it out: 3.76 × 2
  2. 3.76 × 2 = 7.52

I hope this helps!

You might be interested in
Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin
NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)  

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

Assuming that \bar X =5.5 and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=1086-1=1085

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that t_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139    

5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861

So on this case the 95% confidence interval would be given by (5.139;5.861)    We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0
3 years ago
29/5 divided by nine and a half
trapecia [35]

29/5 is 5.8   5.8 dividen by 9 1/2 is 0.61052631578

Hope this helps! Have a great day!!!

3 0
3 years ago
Help me pretty pls i really need help
jok3333 [9.3K]

Answer:

740 or 990

Step-by-step explanation:

It just depends on the height. I don't know if it is 10 or 15. If the height is 15 then 990. If the height is 10 then 740. :)

7 0
3 years ago
Read 2 more answers
Two planes are the same altitude. From the airport , one plane is 50 km away in the direction of N°60 E and another is 80 km awa
djverab [1.8K]

9514 1404 393

Answer:

  78.5 km

Step-by-step explanation:

Measured at the airport, the angle between the two planes is ...

  180° -60° -50° = 70°

The law of cosines tells us the distance between the planes is ...

  d = √(50² +80² -2·50·80·cos(70°)) ≈ √6163.84 ≈ 78.5 . . . km

The planes are about 78.5 km apart.

6 0
2 years ago
(urgent please help!!!!)in computing the mean of 8 numbers, a student mistakenly used 17 instead of 25 as one of the numbers and
mamaluj [8]
I believe the correct mean is 21!
6 0
3 years ago
Read 2 more answers
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