Answer:
7 boxes of pencils and 5 boxes of erasers.
Step-by-step explanation:
The least common denominator of these two numbers are 70. 7×10 and 14×5. So she is purchasing the same quantity of both.
The "origin" of a line is simply the points (0, 0)
To draw a line that passes through the origin (0, 0) & has a slope of 3/5, we simply start by drawing a point at (0, 0).
Then, from there, you use the slope to find your next points.
Slope = rise/run
So, 3 is the rise, and 5 is the run.
So, starting from (0, 0), you go up 3 times, and go to the right 5 times. So, (3, 5) is your next point. Just continue doing that and you'll get a line.
~Hope I helped!~
Answer:
a) 229 and 305 days
b) 229 days or less
c) 305 days or more
Step-by-step explanation:
The Empirical Rule(68-95-99.7 rule) states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 267
Standard deviation = 19
(a) Between what values do the lengths of the middle 95% of all pregnancies fall?_____________and___________days
By the Empirical rule, 95% of all pregnancies fall within 2 standard deviations of the mean.
So
267 - 2*19 = 229 days
to
267 + 2*19 = 305 days
(b) How short are the shortest 2.5% of all pregnancies?______days or less
95% of all pregnancies fall within 2 standard deviations of the mean. The other 5% are more than 2 standard deviations from the mean. Since the distribution is symmetric, 2.5% is more than 2 standard deviations below the mean(shortest 2.5%) and 2.5% is more than 2 standard deviations above the mean(longest 2.5%). So
267 - 2*19 = 229 days
c) How long do the longest 2.5% of pregnancies last?________days or more
Explanation in b)
267 + 2*19 = 305 days
Answer:
104.127 m
Step-by-step explanation
In the question instead of chi, it would be kite.
Given: Distance of Brooke from the base of tree is 50 meters.
The kite is directly above the 10 m tree in the 125 m string is fully extended.
Lets assume the height of the kite be "x".
Its making the Right angle triangle with length of string as hypotenuse, height of kite above tree.
Using Pythagorean formula:
h²= a²+b²
⇒
⇒
⇒ 
Subtracting both side by 2500
⇒ 
Square rooting both side, we know√a²=a
⇒ 
∴ x= 114.127 meter.
Next, we know the value of x include the height of tree.
∴ Height of kite flying above tree= 
⇒ Height of kite flying above tree= 
Hence, the height of kite above the tree is 104.127 meters.
3 is in the thousands
so the answer is 3000
