3 years ago

6k + 2 = 8 -------------------------------------------------------------someone solve.

Mathematics

1 answer:

OverLord2011 [107]3 years ago

4 0

6k=8-2( Since 2 was in addition, it will get subtracted when brought to other side)
6k=6
k=6/6
k=1

You might be interested in

What is the length of BC PLEASE HELP ME ILL GIVE YOU BRAINLIEST

Gnesinka [82]

Answer:

BC = 2.149

7 0

2 years ago

Read 2 more answers

What is equivalent to this equation 4^x+3=64

Umnica [9.8K]

<span><span> x-4/x3-64</span> </span>Final result :<span> x4 - 64x3 - 4 ————————————— x3 </span>

4 0

3 years ago

Read 2 more answers

What linear function represents the line given by the point slope equation y+7= 2/3(x+6)?

Neko [114]

Answer:

the correct answer is the 3rd one

4 0

3 years ago

Read 2 more answers

Probe that:<br><img src="https://tex.z-dn.net/?f=%20%5Csec%20%5Calpha%20%20%5Csqrt%7B1%20-%20%20%5Csin%28%20%7B%7D%5E%7B2%7D%20%

Nataly [62]

Step-by-step explanation:

<h3> $\sec \alpha \sqrt{1 - \sin ^{2} \alpha } = 1$ </h3>

Prove the LHS

Using trigonometric identities

That's

<h3> $\cos ^{2} \alpha = 1 - \sin^{2} \alpha$ </h3>

<u>Rewrite the expression</u>

We have

<h3> $\sec \alpha \sqrt{ \cos^{2} \alpha }$ </h3>

<h3> $\sqrt{ { \cos }^{2} \alpha } = \cos \alpha$ </h3>

So we have

<h3> $\sec \alpha \times \cos \alpha$ </h3>

Using trigonometric identities

<h3> $\sec \alpha = \frac{1}{ \cos \alpha }$ </h3>

<u>Rewrite the expression</u>

That's

<h3> $\frac{1}{\cos \alpha } \times \cos \alpha$ </h3>

Reduce the expression with cos a

We have the final answer as

As proven

Hope this helps you

7 0

3 years ago

Estimate.<br> 40,182 : 2<br> Choose 1 answer:<br> А<br> 20<br> B<br> 200<br> 2,000<br> 20,000

Anvisha [2.4K]

Answer:

20,000

Step-by-step explanation:

3 0

2 years ago