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2 years ago

12

Can someone please help me with this problem? In the picture down below. WILL MARK BRAINLIEST!!!

2 answers:

11111nata11111 [884]2 years ago

4 0

Answer:

only a

Step-by-step explanation:

Svetlanka [38]2 years ago

4 0

Answer: The answer would be B

Step-by-step explanation:

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Pythagorean Theorem.....

pentagon [3]

Step-by-step explanation:

the specific gravity of honey is 1.43. a vat of honey 10 feet deep is inside a dome pressurized to 0.05 atmospheres on the surface of pluto. the total pressure at the bottom of the tub is 7,930 pa. what is the gravitational acceleration of pluto in m/s2

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2 years ago

Geometry // help with this pleaseeee ASAP

babunello [35]

Answer:

A:SPA =CFA by AA

Step-by-step explanation:

Hopefully this helps

6 0

2 years ago

The data to represent average test scores for a class of 16 students includes an outlier value of 78. If the mean, including the

monitta

Answer:

Given that The data to represent average test scores for a class of 16 students includes an outlier value of 78.

We can find sum of all 16 test scores = 84(16) = 1344

Outlier found = 78

If outlier is removed new sum = 1344-78 = 1266

Number of entries without outlier = 15

New average = 1266/12 =84.4

We find that average of new data increases.

Also whenever we remove outlier std deviation also would be reduced.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

On Mars the acceleration due to gravity is 12 ft/sec^2. (On Earth, gravity is much stronger at 32 ft/sec^2.) In the movie, John

insens350 [35]

Solution :

Given initial velocity, v= 48 ft/s

Acceleration due to gravity, g = $12\ ft/s^2$

a). Therefore the maximum height he can jump on Mars is

$H_{max}=\frac{v^2}{2g}$

$H_{max} = \frac{(48)^2}{2 \times 12}$

= 96 ft

b). Time he can stay in the air before hitting the ground is

$T=\frac{2v}{g}$

$T=\frac{2 \times 48}{12}$

= 8 seconds

c). Considering upward motion as positive direction.

v = u + at

We find the time taken to reach the maximum height by taking v = 0.

v = u + at

0 = 16 + (12) t

$t=\frac{16}{12}$

$=\frac{4}{3} \ s$

We know that, $S=ut + \frac{1}{2}at^2$

Taking t = $=\frac{4}{3} \ s$ , we get

$S=16 \times\frac{4}{3} + \frac{1}{2}\times(-12) \times \left(\frac{4}{3}\right)^2$

$S=\frac{32}{3}$ feet

Thus he can't reach to 100 ft as it is shown in the movie.

d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.

Therefore final velocity is = -16 ft/s

3 0

2 years ago

In March, you have $220 in your savings account. By the end of April, your savings have increased by 30%. How much money do you

Lana71 [14]

Answer:

$286

Step-by-step explanation:

220:100=2.2

2.2 x 30 = 66

220+66=286

6 0

3 years ago