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3 years ago

Can someone please help me with this problem? In the picture down below. WILL MARK BRAINLIEST!!!

Mathematics

2 answers:

11111nata11111 [884]3 years ago

4 0

Answer:

only a

Step-by-step explanation:

Svetlanka [38]3 years ago

4 0

Answer: The answer would be B

Step-by-step explanation:

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A human factors expert recommends that there be at least 9 square feet of floor space in a college classroom for every student i

Aliun [14]

I think the answer is 783 square feet.

6 0

3 years ago

Find the general expression for the slope of a line tangent to the curve of y=2x^2+4x at the point P(x,y) . Then find the slopes

ArbitrLikvidat [17]

Complete Question

Find the general expression for the slope of a line tangent to the curve of y=2x^2+4x at the point P(x,y) . Then find the slopes for $x = 3$ and x=0.5. Sketch the curve and the tangent lines. What is the general expression for the slope of a line tangent to the curve of the function y=2x^2+4 at the point P(x,y) ?

Answer:

The generally expression for the slope of $y = 2x^2 + 4x$ is $y' = 4x +4$

The graph is shown on the first uploaded image

The generally expression for the slope of $y=2x^2+4$ is $y' = 4x$

Step-by-step explanation:

From the question we are told that

The equation of the curve is $y = 2x^2 + 4x$

First we differentiate the equation

$y' = 4x +4$

Therefore the generally expression for the slope tangent to the curve $y=2x^2+4x$ is $y' = 4x +4$

The next step is to substitute for x = 3 and x = 0.5

So for $x_1 = 3$

$y' = 4(3) +4$

$y' =m_1= 16$

And for $x_2 = 0.5$

$y' = 4(0.5) +4$

$y' =m_2= 6$

Here m_1 and m_2 are slops of the curve

Next we obtain the coordinates of the tangent lines

So at $x_1 = 3$

$y_1 = 2(3)^2 + 4(3)$

$y_1 = 21$

So the coordinate for the first tangent line is

$(x_1 , y_1 ) = (3 , 21)$

At $x_2 = 0.5$

$y_2 = 2(0.5)^2 + 4(0.5)$

=> $y_2 = 2.5$

So the coordinate for the second tangent line is

$(x_2 , y_2 ) = (0.5 , 2.5)$

Next we obtain the equation for the tangent lines

So generally the slope is mathematically represented as

$m = \frac{y - y_1 }{x-x_1}$

For $(x_1 , y_1 ) = (-3 , 21)$ and $y' =m_1= 16$

$16 = \frac{y -21 }{x-3)}$

=> $y = 16x - 27$

For $(x_2 , y_2 ) = (0.5 , 2.5)$ and $y' =m_2= 6$

$6 = \frac{y -2.5 }{x-0.5}$

$y = 6x -0.5$

Generally the general expression for the slope of a line tangent to the curve of the function y=2x^2+4 at the point P(x,y) is mathematically evaluated by differentiating y=2x^2+4 as follows

$y' = 4x$

7 0

3 years ago

Help guys with the question

Naya [18.7K]

Answer:

$\sin\Big(\dfrac{\theta }{2}\Big) = \dfrac{2\sqrt 5}{5}$

Step-by-step explanation:

$\cos(2x) = \cos^2 x-\sin^2 x = 1-2\sin^2 x \\ \\ \cos(x) = 1-2\sin^2 (\frac{x}{2}) \\ \\ \Rightarrow \sin^2 (\frac{x}{2}) = \dfrac{1-\cos(x)}{2}\\ \\ \sin(\frac{x}{2}) = \pm \sqrt{\dfrac{1-\cos(x)}{2}},\quad x\in [\frac{3\pi }{2},\pi] \Rightarrow \frac{x}{2}\in [\frac{3\pi}{4},\frac{\pi}{2}]\\ \\ \Rightarrow \sin(\frac{x}{2}) > 0 \Rightarrow \sin(\frac{x}{2}) = \sqrt{\dfrac{1-(-\frac{3}{5})}{2}} \Rightarrow \sin(\frac{x}{2}) = \sqrt{\dfrac{8}{10}}=\dfrac{2\sqrt 2}{\sqrt{10}} = \\ \\ =\dfrac{2\sqrt 5}{5}$

7 0

3 years ago

Is the ordered pair a solution of the system? Explain with a sentence.

kotykmax [81]

It is a solution.
Explanation : 2(2)+(1)=5. (2)-(1)=1

Please give brainliest

7 0

3 years ago

Compare 9 x 104 and 5 x 103.

MrRissso [65]

<span>b.9 x 10^4 is 18 times larger than 5 x 10^3
This is a simple matter of floating point division. So let's do that. 9 x 10^4 / 5 x 10^3 First, divide the significands. Giving 9 / 5 = 1.8 And subtract the exponents 4 - 3 = 1 So the result of the division is 1.8 x 10^1 which is 18. So 9x10^4 is 18 times larger than 5x10^3. Now looking at the available options, it's obvious that only "b" is correct.</span>

7 0

3 years ago

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