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Aleks [24]
3 years ago
12

Can someone please help me with this problem? In the picture down below. WILL MARK BRAINLIEST!!!

Mathematics
2 answers:
11111nata11111 [884]3 years ago
4 0

Answer:

only a

Step-by-step explanation:

Svetlanka [38]3 years ago
4 0

Answer: The answer would be B

Step-by-step explanation:

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A human factors expert recommends that there be at least 9 square feet of floor space in a college classroom for every student i
Aliun [14]
I think the answer is 783 square feet.
6 0
3 years ago
Find the general expression for the slope of a line tangent to the curve of y=2x^2+4x at the point P(x,y) . Then find the slopes
ArbitrLikvidat [17]

Complete Question

Find the general expression for the slope of a line tangent to the curve of y=2x^2+4x at the point P(x,y) . Then find the slopes for x = 3 and x=0.5. Sketch the curve and the tangent lines. What is the general expression for the slope of a line tangent to the curve of the function y=2x^2+4 at the point P(x,y) ​?

Answer:

The  generally expression for the slope of y  = 2x^2 + 4x is  y' =  4x +4

The graph is shown on the first uploaded image

The  generally expression for the slope of y=2x^2+4 is   y' =  4x

Step-by-step explanation:

From the question we are told that

  The  equation of the curve is y  = 2x^2 + 4x

First we differentiate the equation

So  

     y' =  4x +4

Therefore the generally expression for the slope tangent to the curve y=2x^2+4x is   y' =  4x +4

The  next step is to substitute for x =  3 and  x =  0.5

So  for x_1 =  3

    y' =  4(3) +4

     y' =m_1=  16

And  for  x_2 =  0.5

      y' =  4(0.5) +4

       y' =m_2=  6

Here m_1  and  m_2 are slops of the curve

Next we obtain the coordinates of the tangent lines

So  at x_1 =  3

   y_1  = 2(3)^2 + 4(3)

  y_1  =  21

So the coordinate for the first tangent line is  

    (x_1 , y_1 ) =  (3 ,  21)

At  x_2 = 0.5      

    y_2  = 2(0.5)^2 + 4(0.5)

=>  y_2  = 2.5

So the coordinate for the second  tangent line is  

    (x_2 , y_2 ) =  (0.5 ,  2.5)

Next we obtain the equation for the tangent lines

 So generally the slope is mathematically represented as

        m  =  \frac{y - y_1 }{x-x_1}

For   (x_1 , y_1 ) =  (-3 ,  21) and  y' =m_1=  16

       16 =  \frac{y -21 }{x-3)}

=>    y   = 16x - 27

For  (x_2 , y_2 ) =  (0.5 ,  2.5) and  y' =m_2=  6

       6  =  \frac{y -2.5 }{x-0.5}

       y  = 6x -0.5

Generally the general expression for the slope of a line tangent to the curve of the function y=2x^2+4 at the point P(x,y) is mathematically evaluated by differentiating  y=2x^2+4 as follows

     y' =  4x

     

7 0
3 years ago
Help guys with the question
Naya [18.7K]

Answer:

\sin\Big(\dfrac{\theta }{2}\Big) = \dfrac{2\sqrt 5}{5}

Step-by-step explanation:

\cos(2x) = \cos^2 x-\sin^2 x = 1-2\sin^2 x \\ \\ \cos(x) = 1-2\sin^2 (\frac{x}{2}) \\ \\ \Rightarrow \sin^2 (\frac{x}{2}) = \dfrac{1-\cos(x)}{2}\\ \\ \sin(\frac{x}{2}) = \pm \sqrt{\dfrac{1-\cos(x)}{2}},\quad x\in [\frac{3\pi }{2},\pi] \Rightarrow \frac{x}{2}\in [\frac{3\pi}{4},\frac{\pi}{2}]\\ \\ \Rightarrow \sin(\frac{x}{2}) > 0 \Rightarrow \sin(\frac{x}{2}) = \sqrt{\dfrac{1-(-\frac{3}{5})}{2}} \Rightarrow \sin(\frac{x}{2}) = \sqrt{\dfrac{8}{10}}=\dfrac{2\sqrt 2}{\sqrt{10}} = \\ \\ =\dfrac{2\sqrt 5}{5}

7 0
3 years ago
Is the ordered pair a solution of the system? Explain with a sentence.
kotykmax [81]
It is a solution.
Explanation : 2(2)+(1)=5. (2)-(1)=1

Please give brainliest
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Compare 9 x 104 and 5 x 103.
MrRissso [65]
<span>b.9 x 10^4 is 18 times larger than 5 x 10^3
    This is a simple matter of floating point division. So let's do that. 9 x 10^4 / 5 x 10^3 First, divide the significands. Giving 9 / 5 = 1.8 And subtract the exponents 4 - 3 = 1 So the result of the division is 1.8 x 10^1 which is 18. So 9x10^4 is 18 times larger than 5x10^3. Now looking at the available options, it's obvious that only "b" is correct.</span>
7 0
3 years ago
Read 2 more answers
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