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3 years ago

Find the distance between the points (–9, 0) and (2, 5). Find the distance between the points (–9, 0) and (2, 5).

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

6 0

Answer:

sqrt( 146)

Step-by-step explanation:

To find the distance, we use the following formula

d = sqrt( ( x2-x1) ^2 + ( y2-y1) ^2)

sqrt( ( -9-2) ^2 + ( 0-5) ^2)

sqrt( ( -11) ^2 + ( -5) ^2)

sqrt( 121+25)

sqrt( 146)

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How to multiply by tens 60×20

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The quadratic regression equation for this data set is $\rm y=-0.143x^2+0.59x+2.82\\$ .

<h3>What is the general form of a quadratic equation?</h3>

The general form of the quadratic equation is given by;

$\rm ax^2+bx+c=0$

Where; a, b, and c are the constants.

x; 0 1 2 3 4 5

y; 2.82 3. 29 3. 46 3. 33 2. 88 2. 24

From the table when the value of x = 0 the value of y is 2.82.

Then,

$\rm y=ax^2+bx+c\\\\x=0\\\\2.82=a0^2+b(0)+c\\\\c=2.82$

From the table when the value of x = 3 the value of y is 3.33.

$\rm y=ax^2+bx+c\\\\x=3\\\\2.82=a(3)^2+b(3)+c\\\\9a+3b+2.82=2.82\\\\9a=-3b\\\\b=-3a\\\\$

From the table when the value of x = 5 the value of y is 2.24.

$\rm y=ax^2+bx+c\\\\x=3\\\\2.24=a(5)^2+(-3a)(5)+c\\\\25a-15a+2.82=2.24\\\\40a=2.24-2.82\\\\10a=-0.68\\\\a= \dfrac{-0.68}{10}\\\\a=-0.143$

And the value of b is;

$\rm b=3a\\\\b=3(-0.14)\\\\b=0.59$

Therefore,

The quadratic regression equation for this data set is;

$\rm y=ax^2+bx+c\\\\y=-0.143x^2+0.59x+2.82\\\\$

Hence, the quadratic regression equation for this data set is $\rm y=-0.143x^2+0.59x+2.82\\$ .

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2 years ago

Radon: The Problem No One Wants to Face" is the title of an article appearing in Consumer Reports. Radon is a gas emitted from t

brilliants [131]

Answer:

a) $\bar{x}$ =4.63 md=4.55 mo= 1.9 b) Sample Standard Deviation≈ 2.58 Coefficient of Variation=55.72% Sample Range=6.9

Step-by-step explanation:

Mean

$a)\bar{x}=\frac{1.9+ 2.3+ 5.7+ 5.2+ 1.9+ 8.8+ 3.9+ 7.3}{8} =\frac{37}{8}=4.625=\approx 4.63$

For the Median, we have to order the entries. So, ordering it goes:

1.9 1.9 2.3 3.9 5.2 5.7 7.3 8.8

Since we have even entries $\frac{\frac{n}{2}+\frac{n}{2} +1}{2}=\frac{4th+5th}{2}=\frac{3.9+5.2}{2}=4.55$

mode

The mode for this data 1.9 1.9 2.3 3.9 5.2 5.7 7.3 8.8 is 1.9

Sample Standard Deviation

Here it is the formula to calculate it:

$_{x}=\sqrt{\frac{\sum (x_{i}-\bar{x})^{2}}{n-1}}\\ S_{x}=\sqrt{\frac{46.855}{7}}\approx 2.58$

Coefficient of Variation

CV is the quocient between sample Standard deviation over Mean and it is used to make comparisons.

$CV=\frac{S_x}{\bar{x}}*100%=\frac{2.58}{4.63} \approx 55.72%$

Range

The difference between the highest and the lowest value of this sample

8.8-1.9=6.9

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3 years ago