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LUCKY_DIMON [66]
3 years ago
6

Find the distance between the points (–9, 0) and (2, 5). Find the distance between the points (–9, 0) and (2, 5).

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
6 0

Answer:

   sqrt( 146)

Step-by-step explanation:

To find the distance, we use the following formula

d = sqrt( ( x2-x1) ^2 + ( y2-y1) ^2)

    sqrt( ( -9-2) ^2 + ( 0-5) ^2)

  sqrt( ( -11) ^2 + ( -5) ^2)

   sqrt( 121+25)

   sqrt( 146)

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Every day, the number of network blackouts has a distribution (probability mass function)
boyakko [2]
Expected Mean, E(X), is obtained by multiplying each pair of x and its P(x) and add up the answers

E(X) = (0×0.7) + (1×0.2) + (2×0.1) = 0.4

The formula to calculate the variance, Var(X), is given by E(X)² - (E(X))²

E(X²) = (0²×0.7) + (1²×0.2) + (2²×0.1) = 0+0.2+0.4 = 0.6
(E(X))² = (0.4)² = 0.16

Var(X) = 0.6 - 0.16 = 0.44

Translating these answers into the context we have

E(Y) = 0.4×500 = $200
Var(Y) = $110

3 0
3 years ago
Which equation has no solution?​
vitfil [10]

The second option

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8 0
2 years ago
Help answers needed
Eddi Din [679]

Answer:

You have to find the gradient, gradient =vertical change ÷horizontal change

6 0
3 years ago
On a science test, 2 points are deducted from a total of 100 points for each question answered incorrectly. Trevor scored an 84
CaHeK987 [17]

Answer:

8

Step-by-step explanation:

Using the equation in the directions (100-2x=84), we can find out how many questions Trevor got wrong on his Science test. First, we need to subtract 100-84=16 to find out how many points he lost. Trevor lost 16 points.  Now we can divide 16/2=8, to find out how many questions he got wrong. Trevor got 8 questions wrong on his test.

Hope this helps!

3 0
3 years ago
Consider the experiment of flipping a coin 4 times where the probability of flipping a heads is 0.18. So each outcome of the exp
seropon [69]

Answer:

0.397

Step-by-step explanation:

In the experiment, if the coin is flipped 4 times, the outcomes in which there is a single heads out of the 4 flips are:

HTTT,THTT,TTHT and TTTH

The probability of flipping a head, P(Head)=0.18

Therefore: The probability of flipping a tail, P(Tail)=1-0.18=0.82

We can then calculate the probability that there is a single heads out of the 4 flips

=P(HTTT)+P(THTT)+P(TTHT)+P(TTTH)

=(0.18 X 0.82 X 0.82 X 0.82) + (0.82 X 0.18 X  0.82 X 0.82) + (0.82  X  0.82 X 0.18 X 0.82 )+ (0.82  X  0.82 X 0.82 X 0.18)

=4(0.18X0.82^3)\\=0.39698496\\\approx 0.397

7 0
3 years ago
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