Question

Factor the numerator and denominator and then reduce the fraction:

Answer 1

$\boxed{\frac{2xy-3y}{x}}$

Explanation:

Here we have the following expression:

$\frac{16xyz-24zy}{8xz} \\ \\ \\ Prime \ factorization: \\ \\ 16=2^4 \\ \\ 24=2^3\cdot 3 \\ \\ 8=2^3$

So we can rewrite this as follows:

$\frac{2^4xyz-2^3\cdot 3zy}{2^3xz} \\ \\ \\ Common \ factor \ 2^3z \ in \ the \ numerator: \frac{2^3z(2xy-3y)}{2^3xz} \\ \\ \\ Commutative \ property \ in \ the \ denominator: \\ \\ \frac{2^3z(2xy-3y)}{2^3zx} \\ \\ \\ Simplyfing: \\ \\ \boxed{\frac{2xy-3y}{x}}$

Learn more:

Simplify: brainly.com/question/10644722

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