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liberstina [14]
3 years ago
9

Hey can you please help me posted picture of question

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0
Answer:
The solutions are: 
\frac{3 + i}{2} and \frac{3 - i}{2}

Explanation:
The general form of the quadratic equation is:
ax² + bx + c = 0
The given equation is:
2x² - 6x + 5 = 0

By comparison:
a = 2
b = -6
c = 5

Now, to get the solutions of the equation, we will have to use the quadratic formula shown in the attached image.

By substituting in the formula, we would find that:
either x = \frac{6 +  \sqrt{(-6)^2 - 4(2)(5)} }{2(2)}  =  \frac{3 + i}{2}

or x = \frac{6 - \sqrt{(-6)^2 - 4(2)(5)} }{2(2)} = \frac{3 - i}{2}

Hope this helps :)

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The inverse of x y is: x y x y y x x y y x
serg [7]

Answer:

The inverse of xy is yx.

Step-by-step explanation:

Given:  xy

We need to find the inverse of xy.

To find inverse of an expression, we need to replace the variable x by y and y  by x.

Given xy.

Now replace x by y and y by x, we get

yx

Therefore, the inverse of xy is yx.

Let me show you an example.

y = x - 2

To find the inverse function, replace x by y and y by x, we get

x = y - 2

It is an equation, to write the equation in terms of y, add 2 from both sides, we get

x + 2 = y -2 + 2

x + 2 = y

Therefore, y = x + 2

5 0
3 years ago
For which pairs of functions is f(g(x))=x?
Nastasia [14]
The answer is B. 
Hope that helps!
Good luck

5 0
3 years ago
Read 2 more answers
An urn contains three red balls and four blue balls. Draw two balls at random from the urn, without replacement. Compute the exp
mezya [45]

Step-by-step explanation:

in total we have 3+4 = 7 balls.

when we draw the first ball, the probability to draw a red ball is 3/7, and a blue ball 4/7.

when we draw the second ball, we have now only 6 balls in total.

the probabilty to draw a red back now depends also on the result of the first draw.

if the first ball was already red, then we have only a chance now of 2 out of 6.

if the first ball was blue, then we have now a chance of 3 out of 6.

so, the probably to draw at least 1 red ball in 2 draws is the probability of drawing one on the first draw plus the probability of drawing one on the second :

1 - probability to see 2 blue balls

1 - 4/7 × 3/6 = 1 - 12/42 = 30/42 = 0.714285714...

the expected number of red balls in 2 draws is

1 red in first red in first red in second

but not second and second but not first

1×(3/7 × 4/6) + 2×(3/7 × 2/6) + 1×(4/7 × 3/6) = 12/42 + 12/42 + 12/42 = 36/42 = 6/7 = 0.857142857 ≈ 0.8571

7 0
2 years ago
A spinner has 8 equal sectors labeled from 1 to 8. The spinner is spun twice.
muminat
On your first spin the chance is 1/2. The same goes for your second spin, but the chance of getting two consecutive even numbers is 1/2 x 1/2.
So the answer is 1/4.
4 0
3 years ago
Read 2 more answers
What is the sum of the first five terms of the geometric sequence in which a1=5 and r=1/5?
Makovka662 [10]
Sum of series of G.P. = Sn = a(1-rⁿ) / 1-r
Here, a = 5
r = 1/5

Substitute their values into the expression:
Sn = 5(1-1/5⁵) / 1 - 1/5
Sn = 5*5/4 [1-1/3125]
Sn = 25/4 [ 3124/3125]
Sn = 781 / 125

In short, Your Answer would be 781/125 in fraction form 
or 6.248 in decimal form

Hope this helps!
3 0
3 years ago
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