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liberstina [14]
3 years ago
9

Hey can you please help me posted picture of question

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0
Answer:
The solutions are: 
\frac{3 + i}{2} and \frac{3 - i}{2}

Explanation:
The general form of the quadratic equation is:
ax² + bx + c = 0
The given equation is:
2x² - 6x + 5 = 0

By comparison:
a = 2
b = -6
c = 5

Now, to get the solutions of the equation, we will have to use the quadratic formula shown in the attached image.

By substituting in the formula, we would find that:
either x = \frac{6 +  \sqrt{(-6)^2 - 4(2)(5)} }{2(2)}  =  \frac{3 + i}{2}

or x = \frac{6 - \sqrt{(-6)^2 - 4(2)(5)} }{2(2)} = \frac{3 - i}{2}

Hope this helps :)

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I found the choices that should have been included in this problem.
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3 years ago
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Answer:

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3 years ago
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Sholpan [36]

Answer:

V (max)  = 2 ft³

and x side of the base is  x  =  0,5 feet

Step-by-step explanation:  See annex ( two different cubes)

We have a square piece of cardboard of  3 inches wide

Let  x be lenght of side to cut in each corner

Then the base of the (future cube) is    3  -  2x,  and the area is  

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Taking derivatives on both sides of the equation

V´(x)  =  12x² - 24x  + 9

V´(x)  =  0       12x² - 24x  + 9  =  0   simplifying   4x² - 8x  + 3  =  0

Second degree equation solving for x

x₁,₂ =  [ 24 ± √( 576) - 432  /24

x₁,₂ =  [24 ±√144 ]/24

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Then we take x  = 0,5  feet

And

V (max)  =  (2)²*0,5   =  4*0,5

V (max)  = 2 ft³

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