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3 years ago

Please help with this problem

Mathematics

2 answers:

Svetlanka [38]3 years ago

6 0

The answer should be 25.64$
You multiple that by 8% and then what you get out of it you add on to what you got as the total .

Marianna [84]3 years ago

4 0

Answer:

I can't see it you got to put the hole paper in the camera

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If a triangle has at least two congruent sides, it is an isosceles triangle. An equilateral triangle has three congruent sides.

Bingel [31]

B. An equilateral is an isosceles triangle

3 0

2 years ago

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Which classification best describes the following system of equations? 3x+6y-12z=36 x=2y-4z=12 4x+8y-16z=48 inconsistent and dep

Viktor [21]

Answer:

Consistent and dependent

Step-by-step explanation:

We are given the following equation:

1. $3x+6y-12z=36$

2. $x+2y-4z=12$

3. $4x+8y-16z=48$

For equation 1 and 3, if we take out the common factor (3 and 4 respectively) out of it then we are left with $x+2y-4z=12$ which is the same as the equation number 2.

There is at least one set of the values for the unknowns that satisfies every equation in the system and since there is one solution for each of these equations, this system of equations is consistent and dependent.

6 0

2 years ago

Find the 4th term Thank you in advance

shepuryov [24]

B1 = 2
b2 = (b1)^2 + 1 = 2^2 + 1 = 5
b3 = (b2)^2 + 1 = 5^2 + 1 = 26

b4 = (b3)^2 + 1 = 26^2 + 1 = 676+1=677

7 0

3 years ago

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Solve pleasee x(7-x)>8

maks197457 [2]

I forgot about this one!! I lbew but I lost it!! Sorry :(

3 0

3 years ago

I need help... I honestly don’t know.

Serhud [2]

Answer:

∡ABC=55°

Step-by-step explanation:

Step 1: Identify all angles

∠A=(x+45)°

∠B=(6x+5)°

∠C=(3x)°

∠ABC=(180-∠B)°=(180-(6x+5))°

Step 2: Use the Triangle Angle Sum Theorem

∠A+∠ABC+∠C=180°

(x+45)+(180-(6x+5))+(3x)=180

x+45+180-6x-5+3x=180

-2x+45+180-5=180

-2x+45-5=0

-2x+40=0

-2x=-40

x=20

Step 3: Plug in x=20 for ∠ABC

∠ABC=(180-(6x+5))°

(180-6(20)-5)°

(180-120-5)°

(60-5)°

55°

So ∡ABC=55°

8 0

2 years ago

Read 2 more answers

Please help with this problem ​

Please help with this problem