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3 years ago

What is the area of the figure?

Mathematics

2 answers:

vodomira [7]3 years ago

7 0

Answer:

I am 99.9% sure it is 57 square feet.

If I am wrong sorry!

Step-by-step explanation:

Have a good rest of your day or night and good luck on your test!

<3 <3 <3

zalisa [80]3 years ago

3 0

Answer: 57 ft²

Step-by-step explanation:

Find the areas of the two individual rectangles and then add that up to find the area of the figure:

Rectangle A: Rectangle B:

= Length * Width = 11.5 * 3

= 7.5 * 3 = 34.5ft²

= 22.5 ft²

Area of figure:

= 22.5 + 34.5

= 57 ft²

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4 times 24 in disruptive property

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Step-by-step explanation:

You got it right! Great job!

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3 years ago

A Right Triangle (ABC) has sides measuring 3 inches and 4 inches. The hypotenuse is 5 inches. A similar right triangle (A'B'C')

fenix001 [56]

Answer:

The length of hypotenuse is 12.5

Step-by-step explanation:

First 7.5 x 7.5 = 56.25

Then 10 x 10 = 100

Add them together 56.25 + 100 = 156.25

Then square root 156.25 and you get 12.5

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3 years ago

Read 2 more answers

What is the derivative of x times squaareo rot of x+ 6?

Dafna1 [17]

Hey there, hope I can help!

$\mathrm{Apply\:the\:Product\:Rule}: \left(f\cdot g\right)^'=f^'\cdot g+f\cdot g^'$
$f=x,\:g=\sqrt{x+6} \ \textgreater \ \frac{d}{dx}\left(x\right)\sqrt{x+6}+\frac{d}{dx}\left(\sqrt{x+6}\right)x \ \textgreater \ \frac{d}{dx}\left(x\right) \ \textgreater \ 1$

$\frac{d}{dx}\left(\sqrt{x+6}\right) \ \textgreater \ \mathrm{Apply\:the\:chain\:rule}: \frac{df\left(u\right)}{dx}=\frac{df}{du}\cdot \frac{du}{dx} \ \textgreater \ =\sqrt{u},\:\:u=x+6$
$\frac{d}{du}\left(\sqrt{u}\right)\frac{d}{dx}\left(x+6\right)$

$\frac{d}{du}\left(\sqrt{u}\right) \ \textgreater \ \mathrm{Apply\:radical\:rule}: \sqrt{a}=a^{\frac{1}{2}} \ \textgreater \ \frac{d}{du}\left(u^{\frac{1}{2}}\right)$
$\mathrm{Apply\:the\:Power\:Rule}: \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1} \ \textgreater \ \frac{1}{2}u^{\frac{1}{2}-1} \ \textgreater \ Simplify \ \textgreater \ \frac{1}{2\sqrt{u}}$

$\frac{d}{dx}\left(x+6\right) \ \textgreater \ \mathrm{Apply\:the\:Sum/Difference\:Rule}: \left(f\pm g\right)^'=f^'\pm g^'$
$\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(6\right)$

$\frac{d}{dx}\left(x\right) \ \textgreater \ 1$
$\frac{d}{dx}\left(6\right) \ \textgreater \ 0$

$\frac{1}{2\sqrt{u}}\cdot \:1 \ \textgreater \ \mathrm{Substitute\:back}\:u=x+6 \ \textgreater \ \frac{1}{2\sqrt{x+6}}\cdot \:1 \ \textgreater \ Simplify \ \textgreater \ \frac{1}{2\sqrt{x+6}}$

$1\cdot \sqrt{x+6}+\frac{1}{2\sqrt{x+6}}x \ \textgreater \ Simplify$

$1\cdot \sqrt{x+6} \ \textgreater \ \sqrt{x+6}$
$\frac{1}{2\sqrt{x+6}}x \ \textgreater \ \frac{x}{2\sqrt{x+6}}$
$\sqrt{x+6}+\frac{x}{2\sqrt{x+6}}$

$\mathrm{Convert\:element\:to\:fraction}: \sqrt{x+6}=\frac{\sqrt{x+6}}{1} \ \textgreater \ \frac{x}{2\sqrt{x+6}}+\frac{\sqrt{x+6}}{1}$

Find the LCD
$2\sqrt{x+6} \ \textgreater \ \mathrm{Adjust\:Fractions\:based\:on\:the\:LCD} \ \textgreater \ \frac{x}{2\sqrt{x+6}}+\frac{\sqrt{x+6}\cdot \:2\sqrt{x+6}}{2\sqrt{x+6}}$

$Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions$
$\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c} \ \textgreater \ \frac{x+2\sqrt{x+6}\sqrt{x+6}}{2\sqrt{x+6}}$

$x+2\sqrt{x+6}\sqrt{x+6} \ \textgreater \ \mathrm{Apply\:exponent\:rule}: \:a^b\cdot \:a^c=a^{b+c}$
$\sqrt{x+6}\sqrt{x+6}=\:\left(x+6\right)^{\frac{1}{2}+\frac{1}{2}}=\:\left(x+6\right)^1=\:x+6 \ \textgreater \ x+2\left(x+6\right)$
$\frac{x+2\left(x+6\right)}{2\sqrt{x+6}}$

$x+2\left(x+6\right) \ \textgreater \ 2\left(x+6\right) \ \textgreater \ 2\cdot \:x+2\cdot \:6 \ \textgreater \ 2x+12 \ \textgreater \ x+2x+12$
$3x+12$

Therefore the derivative of the given equation is
$\frac{3x+12}{2\sqrt{x+6}}$

Hope this helps!

8 0

3 years ago

The average height of two forwards

Gelneren [198K]

Answer:

the other 2 guards must be 6 feet 3 inches

Step-by-step explanation:

$\frac{3(6.8)+2x}{5} =6.6$

5 0

3 years ago

Which values of a, b, and c correctly represent the answer in simplest form? 3 and one-half divided by 2 and one-fourth = a Star

sasho [114]

Answer:

(A) a=1,b=5,c=9

Step-by-step explanation:

We want to simplify $3\frac{1}{2} \div 2\frac{1}{4}$ for values of a, b and c which satisfies: $a\dfrac{b}{c}$

$3\dfrac{1}{2} \div 2\dfrac{1}{4}\\\text{Changing each fraction to improper fraction}\\=\dfrac{7}{2}\div \dfrac{9}{4}\\\text{Next, we change the division sign to multiplication by taking reciprocal of the second fraction}\\=\dfrac{7}{2}X \frac{4}{9}\\=\dfrac{7X4}{2X9}\\=\dfrac{28}{18}\\$ Converting our result to mixed fraction

$\dfrac{28}{18}=1\dfrac{10}{18}=1\dfrac{5}{9}\\a=1,b=5,c=9$

4 0

3 years ago

Read 2 more answers