Answer:
![x_{1} = - \sqrt{2} \: .\: x_{2} = - 1 \: . \: x_{3} = 1 \: . \: x_{4} = \sqrt{2}](https://tex.z-dn.net/?f=%20x_%7B1%7D%20%3D%20%20-%20%20%5Csqrt%7B2%7D%20%20%5C%3A%20%20.%5C%3A%20%20x_%7B2%7D%20%3D%20%20-%201%20%5C%3A%20.%20%5C%3A%20%20x_%7B3%7D%20%3D%201%20%5C%3A%20.%20%5C%3A%20%20x_%7B4%7D%20%3D%20%20%5Csqrt%7B2%7D%20)
Step-by-step explanation:
x⁴ - 3x² + 2 = 0
x^2×2 - 3x² + 2 = 0
(x²)² - 3x² + 2 = 0
t² - 3t + 2 = 0
t = 1, t = 2
x² = 1, x² = 2
x = -1, x = 1
x = - square root 2, x = square root 2
![x_{1} = - \sqrt{2} \: .\: x_{2} = - 1 \: . \: x_{3} = 1 \: . \: x_{4} = \sqrt{2}](https://tex.z-dn.net/?f=%20x_%7B1%7D%20%3D%20%20-%20%20%5Csqrt%7B2%7D%20%20%5C%3A%20%20.%5C%3A%20%20x_%7B2%7D%20%3D%20%20-%201%20%5C%3A%20.%20%5C%3A%20%20x_%7B3%7D%20%3D%201%20%5C%3A%20.%20%5C%3A%20%20x_%7B4%7D%20%3D%20%20%5Csqrt%7B2%7D%20)
You just have to reflect it over the blue line, so if one point is 2 squares from the blue line then you will make it 2 squares away on the other side of the blue line. The y point will stay the same so they will be the same height
Answer:
The area of the sector in circle <em>G</em> formed by segments
, and
is approximately 125.66 square units
Step-by-step explanation:
The given parameters are;
The radius of the circle with center <em>G</em>, r = 15
The measure of the given angle, m∠AGB = 64°
The area of a sector is given as follows;
Area of a sector of a circle = (θ/360°) × π × r²
Therefore;
The area of the sector in circle <em>G</em> formed by segments
, and
is given as follows;
The area of the sector in circle <em>G</em> = (64°/360°) × π × 15² ≈ 125.66 square units
Answer:
A)
Step-by-step explanation:
Let me know if anything is unclear :)
Answer:
.
Step-by-step explanation:
We are given that
and
(because that's the ground), so substituting that into
gives
.