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aleksley [76]
3 years ago
12

Can someone find the surface area please

Mathematics
2 answers:
Elina [12.6K]3 years ago
4 0
The surface area consists of lateral edges area, the upper base and the lower base area.

Find lateral edges area
The lateral edges consists of 3 rectangles with similar dimension, 6 cm long and 3 cm wide.

area = 3 × area of a rectangle
area = 3 × l × w
area = 3 × 6 × 3
area = 54

The area of lateral edges is 54 cm²


Find the surface area

sa = area of lateral edges + area of upper base + area of lower base
sa = 54 + 15.6 + 15.6
sa = 85.2

The surface area of the prism is 85.2 cm²
lozanna [386]3 years ago
3 0
To find the surface area of any object, the first step that you must do is find all shapes that are present in the object.

Here we have 2 triangles and 3 rectangles.

Knowing this, simply find the area of each shape.

Since the triangles are the same, one is facing up and the other down, they both would be 15.6 cm^2.

The rectangles would be 54 cm^2. as there are 3 ( 6 x 3 cm) ones.

Add the values up to have the surface area.

It’s 85.2 cm^2.
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You have decided to purchase a car for $19,000. The credit union requires a 10% down payment and will finance the balance with a
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<h2>○=> <u>Correct option</u> :</h2>

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<h3>○=> <u>Steps to derive correct option</u> :</h3>

Selling price of a car = $19,000

Percentage of sales tax in the city = 8.3%

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2 years ago
The school store opened on the first day of school with 45 notebooks and 15 pencils. Within two days it sold all of these items.
malfutka [58]

The number of pencils sold on the first day  is 5 pencils.

The number of notebooks sold on the first day  is 10 notebooks.

The number of pencils sold on the second day 10 pencils.

The number of notebooks sold on the second day   35 notebooks.

<u>Step-by-step explanation:</u>

Given data,

  • The total number of notebooks in the store = 45 notebooks.
  • The total number of Pencils in the store = 15 pencils.
  • The number of days that all items were sold = 2 days.

Now, you have to calculate the no.of notebooks and no. of pencils sold each day.

<u>In the first day :</u>

The number of sale of notebooks and pencils are given by,

Twice as many notebooks were sold as pencils.

Let us take, the number of pencils sold on the first day  = x

And,  the number of notebooks sold on the first day  = 2x (Twice as pencils).

<u>In the second day :</u>

The number of sale of notebooks and pencils are given by,

For every 7 notebooks​ sold, 2 pencils were sold.

The number of pencils sold on the second day =   2y

The number of notebooks sold on the second day   = 7y

<u> The equation is framed for number of notebooks sold on each day :</u>

The number of notebooks sold ⇒ 2x + 7y = 45   -------(1)

<u> The equation  is framed for number of pencils sold on each day :</u>

The number of pencils sold: x + 2y = 15  ----------(2)

Solving the equations by multiplying eq(2) by 2 and subtract it from eq(1),

  2x + 7y = 45

-<u> (2x + 4y) = 30</u>

   <u>        3y = 15  </u>

⇒ y = 15/3

⇒ y = 5

The value of y is 5.

Substitute y=5 in eq (2),

⇒ x + 2(5) = 15

⇒ x + 10 = 15

⇒ x = 15 - 10

⇒ x = 5

The value of x is 5.

First day sale,

The number of pencils sold on the first day  = x ⇒ 5 pencils

The number of notebooks sold on the first day  = 2x ⇒ 10 notebooks

Second day sale,

The number of pencils sold on the second day =   2y ⇒ 10 pencils

The number of notebooks sold on the second day   = 7y ⇒ 35 notebooks.

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