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neonofarm [45]
3 years ago
8

What is used in computers to communicate with wireless keyboards, mice, and printers?

Computers and Technology
1 answer:
vekshin13 years ago
5 0
Usb adapter -----------
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Lonic compounds are also known as <br> a. salts <br> b. valence <br> c.organic <br> d.elements
shutvik [7]
I'm not quite sure but it maybe b
6 0
3 years ago
Read 2 more answers
In JAVA please:
blagie [28]

Answer:

import java.util.Scanner;

public class ArraysKeyValue {

public static void main (String [] args) {

final int SIZE_LIST = 4;

int[] keysList = new int[SIZE_LIST];

int[] itemsList = new int[SIZE_LIST];

int i;

keysList[0] = 13;

keysList[1] = 47;

keysList[2] = 71;

keysList[3] = 59;

itemsList[0] = 12;

itemsList[1] = 36;

itemsList[2] = 72;

itemsList[3] = 54;  

/* Your solution goes here */

for ( i = 0; i < SIZE_LIST; i++){

 if (keysList[i]>50){

  System.out.println(itemsList[i] + " ");  }  }

System.out.println("");

}

}

Explanation:

I will explain the whole program flow.

  • There are two arrays here
  • keysList and itemsList
  • The first list (keysList) contains the following elements:

13 element at first position of the array (0th index)

47 element at second  position of the array (1st index)

71 element at third position of the array (2nd index)

59 element at fourth position of the array (3rd index)

  • The other list (itemsList) contains the following elements:

12 element at first position of the array (0th index)

36 element at second  position of the array (1st index)

72 element at third position of the array (2nd index)

54 element at fourth position of the array (3rd index)

  • The size of the array elements is fixed which is 4 and is stored in the variable SIZE_LIST.
  • Then the loop starts. The loop contains a variable i which is initialized to 0. First it checks if the value of i is less than the size of the list. It is true as SIZE_LIST=4 and i=0.
  • So the program control enters the body of the loop.
  • In first iteration, IF condition checks if the i-th element of the keysList is greater than 50. As i=0 So the element at 0th index of the keysList is 13 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i increments by 1 so now i becomes 1.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=1 So the element at 1st index of the keysList is 47 which is not greater than 50 so the body of IF statement will not execute as the condition evaluates to false. The value of i is incremented by 1 so now i becomes 2.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 2 which is less than SIZE_LIST so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=2 So the element at 2nd index of the keysList is 71 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 2 so the value at the index 2 of the itemsList is displayed in the output which is 72. Next value of i is incremented by 1 so now i becomes 3.
  • In next iteration loop again checks if the value of i is less than the size of the list which is true again as i= 3 which is less than SIZE_LIST so the body of the loop executes.
  • IF condition checks if the i-th element of the keysList is greater than 50. As i=3 So the element at 3rd index of the keysList is 59 which is greater than 50 so the body of IF statement is executed as the condition evaluates to true. So in the body of the IF statement there is a print statement which prints the i-th element of the itemsList. As i = 3 so the value at the index 3 of the itemsList is displayed in the output which is 54. Next value of i is incremented by 1 so now i becomes 4.
  • In next iteration loop again checks if the value of i is less than the size of the list which is now false as i=4 which is equal to the SIZE_LIST= 4. So the loop breaks.
  • So the output of the above program is:

72

54

5 0
3 years ago
Match each of the following steps of SDLC development to its position in the development process.
Arisa [49]

Answer:

Step One - problem/opportunity identification  (V)

Step Two - Analysis (III)

Step Three - Design (II)

Step Four - Development (I)

Step Five - Testing and Installation (IV)

Explanation:

In the field of software development, or systems engineering, SDLC which refers to software development cycle refers to a systematic way of building software applications, it shows unique stages with the outcome of each stage dependent on the previous, step has a unique task which range from the planning, analysis, development, testing and installation of the information system.

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4 years ago
What is the difference between 1080p and 2k?
professor190 [17]
They have the same  vertical resolution. I can suggest you to watch the video in youtube .<span>https://www.youtube.com/watch?v=uluEEGBHyUE</span>
7 0
3 years ago
In Python, if var1 = "Happy" and var2= "Birthday" and var3 = (var 1+var2) *2, then var3 stores the string
nordsb [41]

Answer:

The answer is "Option A".

Explanation:

The program to the given question can be given as:

program:

var1 = "Happy" #defining variable var1

var2= "Birthday" #defining variable var2

var3 = (var1+var2) *2 #defining variable var3 and calculate value

print (var3) #print value.

Output:

HappyBirthdayHappyBirthday

In the above python program, three variable is defined, that is var1, var2, and var3, in which variable var1 and var2 we assign a value, that is "Happy" and "Birthday".

In variable var3 we add the value of var1 and var2 variable and multiply by 2. It will print the variable value two times. and other options are not correct that can be defined as:

  • In option B and C, Both variable var1 and var2 print there values two times but in option B var1 value print two time and var2 value print one time only and option C var1 variable value is print only one time and var2 variable value is print two times that's why it is not correct.
  • In option C, Both variable var1 and var2 print there values two times that's why it is not correct.

7 0
3 years ago
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