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Lady bird [3.3K]
3 years ago
6

In Python, if var1 = "Happy" and var2= "Birthday" and var3 = (var 1+var2) *2, then var3 stores the string

Computers and Technology
1 answer:
nordsb [41]3 years ago
7 0

Answer:

The answer is "Option A".

Explanation:

The program to the given question can be given as:

program:

var1 = "Happy" #defining variable var1

var2= "Birthday" #defining variable var2

var3 = (var1+var2) *2 #defining variable var3 and calculate value

print (var3) #print value.

Output:

HappyBirthdayHappyBirthday

In the above python program, three variable is defined, that is var1, var2, and var3, in which variable var1 and var2 we assign a value, that is "Happy" and "Birthday".

In variable var3 we add the value of var1 and var2 variable and multiply by 2. It will print the variable value two times. and other options are not correct that can be defined as:

  • In option B and C, Both variable var1 and var2 print there values two times but in option B var1 value print two time and var2 value print one time only and option C var1 variable value is print only one time and var2 variable value is print two times that's why it is not correct.
  • In option C, Both variable var1 and var2 print there values two times that's why it is not correct.

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Question No. 5:
Mkey [24]

Answer:

The answers are:

a) (1001111)_2 = (79 )_{10}\\b) (11000001)_2 = (C1 )_{16}\\c) (E16)_{16} = ( 3606)_{10}\\d) (56)_{10} = (38 )_{16}\\e) (63)_{10}= (111111 )_2

Explanation:

<u>a. (1001111) 2 = ( ) 10</u>

In order to convert a base 2 number to base 10 number system the place values are used.

the procedure is as follows:

(1001111)_2\\=(1*2^6)+(0*2^5)+(0*2^4)+(1*2^3)+(1*2^2)+(1*2^1)+(1*2^0)\\=(1*64)+(0*32)+(0*16)+(1*8)+(1*4)+(1*2)+(1*1)\\=64+0+0+8+4+2+1\\=79

<u>b) (11000001) 2 = ( ) 16</u>

In order to convert a base 2 number into base 16, group of 4-bits are made starting from right to left

The groups from the given number are:

1100 0001

Then the groups are changed in to decimal/hexa

So,

(1100)_2 = (1*2^3)+(1*2^2)+(0*2^1)+(0*2^0)\\=(1*8)+(1*4)+(0*2)+(0*1)\\=8+4+0+0=12=C\\\\0001=1

Writing in the same order in which groups were:

(C1)_{16}

<u>c) (E16) 16 = ( ) 10</u>

(E16)_{16}\\=(E*16^2)+(1*16^1)+(6*16^0)\\=(E*256)+(1*16)+(6*1)\\=3584+16+6\\=3606

<u>d) (56) 10 = ( ) 16</u>

Dividing by 16 and noting remainders

16        56

           3 - 8

So,

The number in base 16 is 38

<u>e) (63) 10 = ( ) 2</u>

Dividing by 2

2         63

2         31 - 1

2         15 - 1

2          7 -  1

2          3 -  1

            1 - 1

So the  number after converting in base 2 is:

111111

Hence,

The answers are:

a) (1001111)_2 = (79 )_{10}\\b) (11000001)_2 = (C1 )_{16}\\c) (E16)_{16} = ( 3606)_{10}\\d) (56)_{10} = (38 )_{16}\\e) (63)_{10}= (111111 )_2

8 0
3 years ago
How do you activate the Slicer Tools contextual tab?
Strike441 [17]

Answer:

i need this one too

Explanation:

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which of these tools stick to the edge of an image, thus making it easy to select the shape of an image
USPshnik [31]

Answer:

ljb lih lug outbpiyougvotvoy

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Explanation:

didn't understand the question

3 0
3 years ago
Write a program that takes in a positive integer as input, and outputs a string of 1's and 0's representing the integer in binar
Mashcka [7]

Answer:

Following are the code to this question:

def binarynumber(num):#defining a method binarynumber that accepts a parameter num

   x=""#defining a string variable x

   if (num!=0):#defining if condition to check number not equal to 0

       while (num>=1):#defining a loop that check value is grater then equal to one

           if (num %2==0):#defining if condition to check num is even

               x=x+"0" #add string value 0 in num variable

               num=num/2 #divide the value by 2

           else:#defining else block

               x=x+"1"#add string value 1 in num variable

               num=(num-1)/2#first subtract 1 into num variable then divide the value by 2

   else:

       x="0"#assign string value 0 in num variable  

   return "".join(reversed(x))#return value

num = int (input ("Enter any number: "))#defining num variable that input the integer value

print (binarynumber(num))#using print method to call method binarynumber with passing num parameter

Output:

Enter any number: 12

1100

Explanation:

  • In the above python code a method "binarynumber" is declared, in which the "num" variable passes as the parameter inside the method a string variable "x" is declared that stores all converted values.
  • Inside the method and if the block is declared that checks number value is not equal to 0 if this condition is false then it will add string value and reverse its value.
  • Or if the condition is true it defines a while loop that calculates the given number binary digits and returns its value.
  • At the last step, the num variable is declared that inputs the integer value from the user end and calls the method by using the print method.    
6 0
4 years ago
Select
valentinak56 [21]

Answer:

return values.remove() + values.remove();

Explanation:

The appropriate expression to complete the method, which is designed to return the sum of the two smallest values in the parameter array number is indicated below in bold font :

public static int

sumTwoLowestElements(int[] numbers)

{

PriorityQueue values = new PriorityQueue<>();

for (int num: numbers)

{ values.add(num);

}

return values.remove() + values.remove();  

}

The return statementin programming is often used when a function is ready to return a value to its caller.

6 0
3 years ago
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