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lys-0071 [83]
3 years ago
13

The length of the base of a rectangular prism is 9

Mathematics
1 answer:
Tatiana [17]3 years ago
7 0

Answer:

The volume of the prism is <u>320 15/16 inches³</u>.

Step-by-step explanation:

Given:

The length of the base of a rectangular prism is 9 7/8.

The width of the prism is 8 1/8.

And the height is 4 inches.

Now, to find the volume of the prism.

(Length) <em> l = 9 7/8 = 79/8 inches.</em>

(Width)  <em> w = 8 1/8 = 65/8 inches</em>.

(Height)  <em>h = 4 inches</em>.

So, by putting the formula to get the volume:

Volume = w×h×l.

Volume=\frac{65}{8}\times 4\times \frac{79}{8}

Volume=320\frac{15}{16}

<em>Volume = 320 15/16 inches³.</em>

Therefore, the volume of the prism is 320 15/16 inches³.

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The circle below is centered at the origin and has a radius of 4. What is its
BlackZzzverrR [31]

Answer:

Step-by-step explanation:

The standard form of a circle's equation is

(x-h)^2+(y-k)^2=r^2 where h and k are the circle's center and r is the radius. We are told, and we can see, that the center of the circle is (0, 0) so h = 0 and k = 0. The radius, given as 4, goes into the equation squared, so the equation is

(x-0)^2+(y-0)^2=16 which simplifies down to

x^2+y^2=16, choice C.

8 0
3 years ago
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s Chegg uppose you have purchased a filling machine for candy bags that is supposed to fill each bag with 16 oz of candy. Assume
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Answer:

it 68.9

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because u add all that

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2 years ago
The heat in the house is set to keep the minimum and maximum temperatures (in degrees Fahrenheit) according to the equation |x –
olga2289 [7]

Given the equation |x-72.5|=4.

When x is maximum, we have

|x-72.5|= x-72.5. Hence x-72.5 =4\\x=76.5

The maximum temperature is 76.5\; ^oF

When x is minimum, we have

|x-72.5|=72.5-x. Hence 72.5-x =4\\x=68.5

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I already solved this problem. I just need help with the HINT part.
frutty [35]
x+y=25 \\ y=25-x~~Other~number~in~terms~of~x \\ \\ x^2+y^2=313 \\ x^2+2xy+y^2=313+2xy \\ (x+y)^2=313+2x(25-x) \\ \frac{25^2-313}{2} =25x-x^2 \\ x^2-25x+156 \\ \\ \Delta =(-25)^2-4\times 1\times 156 \\ \Delta =625-624 \\ \sqrt{\Delta}=1 \\ \\ x= \frac{25 \pm 1}{2} \\ x= \left \{ {{x_1=13} \atop {x_2=12}} \right.

     The number "x" is given by:
y= \left \{ {{y_1=25-13 \rightarrow~y_1=12} \atop {y_1=25-12 \rightarrow ~y_1=13}} \right.
  
     Therefore, we have:

\boxed {S=({12,13})} \rightarrow~The~curly~braces~does~not~want~appear~here.
8 0
3 years ago
Please help me i'm being timed
Evgen [1.6K]

To Find :-

  • The algebraic equations to solve the above problem .

Solution :-

Let ,

  • Large number = L
  • Small number = S

— According to first statement ,

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  • L - S - 4 = 0

— According to second statement ,

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  • 3L + 4S - 54 = 0 .

These equations matches with the second option b .

Option b is the correct answer.

7 0
2 years ago
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