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lana [24]
4 years ago
14

Urgent help please

Mathematics
1 answer:
andrew-mc [135]4 years ago
6 0

Mean is the arithmatic average of a given data set. So,

Mean= \frac{Sum of the data}{Number of the data}

There are seven data in the data set.

According to the given problem,

\frac{18+p+13+q+15+r+7 }{7} =11

\frac{53+p+q+r }{7} =11 Combine the like terms of the numerator.

\frac{53+p+q+r }{7}*7 =11 *7 Multiplying 7 to each sides of equation.

53 + p + q + r = 77

53 + p + q + r - 53 = 77 - 53 Subtract 53 from each sides.

p + q + r = 24

Next step is to divide each sides by 3 so that we can write this in form of mean of p, q and r. Therefore,

\frac{p + q + r}{3} =\frac{24}{3}

So, mean of p, q and r = 8.

I hope this helps you!.

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3 0
4 years ago
3. Write out the prime factor of the following numbers.<br> a. 15<br> b. 21<br> C. 38<br> d. 42
Minchanka [31]

Answer:

The prime factors of 15 are: 1,3,5,15

The prime factors of 21 are: 1,3,7,21

The prime factors of 38 are: 1,3,13,39

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6 0
3 years ago
Solve for the variable<br> x- 8= – 8
Lyrx [107]

Answer:

x=0

Step-by-step explanation:

X -8 = -8

Add 8 to both sides to get x alone

X = 8 - 8

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3 0
3 years ago
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Homework help, please
Vinvika [58]
Start the line at 3 on the y-axis (vertical). then go down two boxes and to the right three & make a mark at that point. keep going down two and over three until the end of the graph. then just connect the marks.
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3 years ago
If f(x)=x^2-1 and g(x)=-2x-3, what is the domain of (fog)(x)?
Iteru [2.4K]

Answer:

The domain of (fog)(x)  is  \begin{bmatrix}-8  , -1\end{bmatrix}

Step-by-step explanation:

Given function as :

f(x) = x² - 1      And

g(x) = - 2x - 3

So, Function (fog)(x) = ( -2x - 3 )² - 1

Or,  (fog)(x) = ( 4x²  + 12x + 9) - 1

Or,   (fog)(x) =  4x²  + 12x + 8

Or,   (fog)(x) =  4x²  + 4x + 8x + 8

Or,   (fog)(x) = 4x ( x + 1 ) + 8 ( x + 1 )

Or,   (fog)(x) =  ( 4x + 8 ) ( x + 1 )

∴    (fog)(x)  lies between  - 8 to - 1

Hence The domain of (fog)(x)  is  \begin{bmatrix}-8  , -1\end{bmatrix}    Answer

6 0
4 years ago
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