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3 years ago

What is a collection of data that is stored in a computer system

2 answers:

6 0

A named collection of data stored on a computer disk is called a file. Files are settings, commands or information that are used by a computer program to perform a certain function.

Vitek1552 [10]3 years ago

4 0

0 and 1's are stored in a computer which is converted into a electric signal that goes to the screen and keyboard which sends a signal back

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The multitasking, multi-user, operating system developed by Bell Laboratories that operates on a wide variety of computing platf

olasank [31]

Answer:

Unix

Explanation:

UNIX is simply an operating system developed by Bell Laboratories in the 1960s. Ever since then, it has been constantly worked upon and developed. It is an operating system because it is a suite of programs capable of making a computer to function. Unix is considered to be a stable, multi-user, and multi-tasking system for both desktops and laptops and even servers.

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3 years ago

Define the types of objects that can be stored in active directory, such as user or computer accounts.

nevsk [136]

Schema classes define all objects that AD can handle.

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4 years ago

Variance for accumulator. Validate that the following code, which adds the

Art [367]

Using the knowledge of computational language in JAVA it is possible to write a code that Validate that the following code, which adds the methods var() and stddev() to Accumulator, computes both the mean and variance of the numbers presented as arguments to addDataValue()

<h3>Writting the code:</h3>

import java.util.*;

public class Accumulator {

private static double m;

private static double v;

private static double st;

private static double s[]=new double[5];

private static int N;

private static int count =0;

public static void main(String[] args) {

// TODO Auto-generated method stub

Random r = new Random();

System.out.println("hello world");

for(int i=0;i<5;i++) {

double randomvalue = r.nextDouble();

addDataValue(randomvalue);

}

for(int i=0;i<s.length;i++) {

System.out.println("dataValue:"+s[i]);

}

mean();

System.out.println("mean:"+m);

var();

System.out.println("variance:"+v);

stddev();

System.out.println("standard deviation:"+st);

}

public static void addDataValue(double value) { // addes data values to array

s[count]=value;

count++;

}

public static double mean() { // returns mean

double sum=0.0;

for(int i=0;i<s.length;i++) {

sum+=s[i];

}

m = sum/s.length;

return m;

}

public static double var() { //returns variance

double mm = mean();

double t = 0;

for(int i=0;i<s.length;i++) {

t+= (s[i]-mm)*(s[i]-mm);

}

v= t/(s.length-1);

return v;

}

public static double stddev() { // returnsn the stardard deviation

st= Math.sqrt(var());

return st;

}

See more about JAVA at brainly.com/question/12975450

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3 0

1 year ago

To serve as a visual reminder that the structure or class name is not a variable, structure names and class names should _______

GrogVix [38]

be clearly marked as distinct from variables. Instead, they should be marked or labeled otherwise, and an explicit indication that they are not variables should be provided both next to the structure and class names, and also on a separate visual material.

7 0

4 years ago

Given an array of values which initially contains 9 8 7 6 5 4 3 2 1, what does the array look like after bubble sort has execute

Phantasy [73]

Answer:

//Here is code in C++.

//include header

#include <bits/stdc++.h>

using namespace std;

// function to print the array

void out_arr(int inp[], int len)

{

for (int i = 0; i < len; i++)

cout << inp[i] << " ";

cout << endl;

}

// main function

int main()

{

// decalare and initialize the array

int inp[] = {9,8,7,6,5,4,3,2,1};

//find the length of array

int len = sizeof(inp)/sizeof(inp[0]);

int x, y;

// perform bubble sort, only 3 pass

for (x = 0; x < 3; x++)

{

for (y= 0; y< len-x-1; y++)

if (inp[y] > inp[y+1])

{

int t=inp[y];

inp[y]=inp[y+1];

inp[y+1]=t;

}

cout<<"array after "<<x+1<<" pass"<<endl;

// print the array after every pass

out_arr(inp, len);

}

return 0;

}

Explanation:

Declare an integer array "inp" and initialize with {9,8,7,6,5,4,3,2,1}. Find the length of the array.In first pass of bubble sort, largest value is placed at the correct position in the array. And in the second, second largest value is placed at its correct position. After the n pass, array will be sorted. In each pass, each element is compared with the next element. if the value is greater than swap them. This continues for all elements in each pass. In the end of a pass a value is placed correctly. So if there is only 3 pass then 3 largest values will be placed at their right place.

Output:

8 7 6 5 4 3 2 1 9

array after 2 pass

7 6 5 4 3 2 1 8 9

array after 3 pass

6 5 4 3 2 1 7 8 9

7 0

3 years ago