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kvv77 [185]
2 years ago
9

48a2 + 32a2 + 16a by 4a?

Mathematics
2 answers:
lbvjy [14]2 years ago
7 0

(48a^3 + 32a^2 + 16a) / 4a = ?

48a^3 / 4a = 12a^2

32a^2 / 4a = 8a

16a / 4a = 4

so

(48a^3 + 32a^2 + 16a) / 4a = 12a^2 + 8a + 4

Answer is D. 12a^2 + 8a + 4

Vladimir [108]2 years ago
7 0

In a similar way to how we distribute multiplication across addition (ex: 2 x (3 + 2) = 2 x 3 + 2 x 2) we can distribute this division, too. We divide each term individually by 4a, and then add them back together again:

48a^3\div4a=12a^2 \\ 32a^2\div4a=8a\\ 16a\div4a=4

Adding all those divided terms together, we get the expression 12a² + 8a + 4, which is D.

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Answer:

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Step-by-step explanation:

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We also know that the centroid is 2/3 of the distance from each vertex to the midpoint of the opposite side.

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7 0
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