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kompoz [17]
2 years ago
13

If a cone has a radius of 6 cm and the height of 18 cm what is it's volume ?

Mathematics
1 answer:
VLD [36.1K]2 years ago
4 0
The volume is V≈678.58cm³
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A fair die is rolled repeatedly. find the expected number of rolls until all 6 faces appear.
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Each face has a chance of 1/6
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8 0
3 years ago
Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca
Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

\frac{dQ}{dt} = -rt

Which has the following solution:

Q(t) = Q(0)e^{-rt}

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that Q(6) = (1-0.03)Q(0) = 0.97Q(0). We use this to find r.

Q(t) = Q(0)e^{-rt}

0.97Q(0) = Q(0)e^{-6r}

e^{-6r} = 0.97

\ln{e^{-6r}} = \ln{0.97}

-6r = \ln{0.97}

r = -\frac{\ln{0.97}}{6}

r = 0.0051

So

Q(t) = Q(0)e^{-0.0051t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.0051t}

0.5Q(0) = Q(0)e^{-0.0051t}

e^{-0.0051t} = 0.5

\ln{e^{-0.0051t}} = \ln{0.5}

-0.0051t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.0051}

t = 135.9

The half-life of the radioactive substance is 135.9 hours.

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2 years ago
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2 years ago
What is 17x-2xy+3x+10xy
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The answer is 14x + 8xy
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3 years ago
Read 2 more answers
If x is 6, What is X+4
hichkok12 [17]

Answer:

x = 10

Step-by-step explanation:

We know x = 6

asked: x + 4

Plus it in =>

6 + 4

=> 10

8 0
3 years ago
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