Question

What is the solution to the equation Two-thirds x + 1 = one-sixth x minus 7? x = negative 16 x = negative 4 x = 4 x = 16

Answer 1

Answer:

x = -16

Step-by-step explanation:

Step 1: Write out equation

2/3x + 1 = 1/6x - 7

Step 2: Subtract 1/6x on both sides

1/2x + 1 = -7

Step 3: Subtract 1 on both sides

1/2x = -8

Step 4: Multiply 2 on both sides

x = -16

Answer 2

Answer:

x = -16

Step-by-step explanation:

I was able to come to this conclusion by first giving $\frac{1}{6}$ and $\frac{2}{3}$ a common denominator.

$\frac{4}{6} x +1 = \frac{1}{6}x -7$

From here all I had to do was simply simplify on both sides so I subtracted $\frac{1}{6}$ from both sides of the equation and got

$\frac{3}{6}x + 1 = -7$

From the there I then subtracted the 1 from both sides of the equation so that the variable and the real number would be on different sides of the equal sign.

$\frac{3}{6}x = -8$

Then I had to isolate the $x$ so I divided both sides by $\frac{3}{6}$ and got -16.