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4 years ago

Solve for x: 4|2x − 2| + 10 = 34.

Mathematics

1 answer:

Alexeev081 [22]4 years ago

6 0

x = 4, x = −2 would be the answer to your first question

I hope this helps :)

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Richard, Henry and Gavin share some sweets in the ratio 5:4:3. Richard gets 70 sweets. How many sweets are there altogether?

maxonik [38]

There are 168 sweets altogether

<h3>Solution:</h3>

Richard, Henry and Gavin share some sweets in the ratio 5 : 4 : 3

Let "5a" be the share of Richard

Let "4a" be the share of Henry

Let "3a" be the share of Gavin

Richard gets 70 sweets

share of Richard = 70

5a = 70

To find: number of sweets altogether

number of sweets altogether = share of richard + share of henry + share of gavin

number of sweets altogether = 5a + 4a + 3a

number of sweets altogether = 12a = 12(14) = 168

Thus there are 168 sweets altogether

4 0

3 years ago

An online video store charges $24 for each DVD. Shipping costs $4 per order. Write a variable expression for the cost of orderin

svp [43]

Answer:

24d+4

Step-by-step explanation:

3 0

4 years ago

The difference of two numbers is 3. their sum is 14. find the two numbers. (show work please)

Artemon [7]

Let's say the larger number is x. that means that the smaller number is x - 3. since you know their sum is x + x - 3, and that is equal to 14. so you have the equation x + x - 3 = 14. combine like terms (x) to get 2x - 3 = 14. add three to both sides to get 2x = 17. divide both sides by two to get x = 17/2. so the larger number is 17/2, and the larger number is 11/2 (17/2 - 3 = 11/2)

8 0

3 years ago

Find an equation of the line whose intercepts are twice those of the graph of 5y+2x=10.

sertanlavr [38]

5y+2x=10y=−25x+2246810−2−4−6−8−10246810−2−4−6−8−10Let's solve for x.5y+2x=10Step 1: Add -5y to both sides.2x+5y+−5y=10+−5y2x=−5y+10Step 2: Divide both sides by 2.2x2=−5y+102x=−52y+5Answer:x=−52y+5

6 0

4 years ago

Read 2 more answers

Find the interquartile range of the following data set.

BigorU [14]

The interquartile range of 48, 26, 31, 50, 38, 40, 42, 34, 44, 36, is: D. 10.

<h3>What is the Interquartile Range of a Data Distribution?</h3>

The interquartile range of a data distribution is determined as: upper quartile (Q3) - lower quartile (Q1).

<h3>How to Find the Upper Quartile and Lower Quartile of a Data Distribution?</h3>

The upper quartile of a data distribution is the center of the second half of a data distribution while the lower quartile is the center of the first half of a data distribution.

Given the data, 48, 26, 31, 50, 38, 40, 42, 34, 44, 36:

Order the data set as, 26, 31, 34, 36, 38, 40, 42, 44, 48, 50

The first half of the data is: 26, 31, 34, 36, 38.

The center is 34.

Lower quartile (Q1) = 34.

The second half of the data is: 40, 42, 44, 48, 50. The center is 44.

Upper quartile (Q3) = 44.

Interquartile range = 44 - 34

Interquartile range = 10

Learn more about interquartile range on:

brainly.com/question/4102829

#SPJ1

6 0

2 years ago