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3 years ago

Hannah has 283 charms to decorate bracelets. If she wants to put 5 charms on each bracelet, how many bracelets can she make

Mathematics

2 answers:

FromTheMoon [43]3 years ago

4 0

She can make 56 bracelets and have 3 charms left over

SashulF [63]3 years ago

4 0

ok so if its division the anwser would be 56.6

if its multiplaication the awnser would be 1415

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Feliz [49]

Notice that it starts at x = 0 with closed dot then it goes to the right.

So the domain would be {x | x ≥ 0}

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3 years ago

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Find the value of y so that WX is perpendicular to YZ

Alexxandr [17]

step 1

Find out the slope WX

W(2,-3) and X(-4,9)

m=(9+3)/(-4-2)

m=12/-6

m=-2

step 2

Find out the slope YZ

Y(5,y) and Z(-1,1)

m=(1-y)/(-1-5)

m=(1-y)/-6

m=(y-1)/6

step 3

Remember that

If two lines are perpendicular

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their slopes are negative reciprocal

that means

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8 0

1 year ago

Hamdi lives 452 miles from her

scZoUnD [109]

Answer:

It's 317 miles.

Step-by-step explanation:

You just take the amount of miles it is from her grandparents house and the amount of miles to her cousins house and then you subtract them.

452-135=317 miles apart.

7 0

3 years ago

Two cars leave from a town at the same time traveling in opposite directions. One travels 5 mph faster than the other. In 3 hour

Doss [256]

Let the slower cars speed equal X.

The faster cars speed would be X+5 ( 5 mph faster).

They traveled for 3 hours

Multiply the time of travel by speed to equal the number of miles traveled.

So you have:

3X + 3(X+5) = 267 miles

Simplify the left side:

3X + 3X+15 = 267

Combine like terms:

6x + 15 = 267

Subtract 15 from each side"

6x = 252

Divide each side by 6:

x = 252 / 6

X = 42

The slower car was traveling at 42 mph and the faster car was traveling at 47 mph.

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3 years ago

I. Daska is situated at a distance of 15 miles from both Gujranwala and Sialkot. A bus travels from Gujranwala to Daska at an av

son4ous [18]

Answer:

The average speed of the entire trip is 8.5 miles per hour.

Step-by-step explanation:

Speed = Total Distance / Total Time

So we have to find the total distance and the total time taken .

1) From Gujranwala to Daska

speed= 25miles/hour distance = 15miles

Time taken = distance / speed

= 15/25= 0.6 hours

2) From Daska to Sialkot

speed= 40miles/hour distance = 15miles

Time taken = distance / speed

= 40/15= 2.67 hours

3 ) From Sialkot to Daska

speed= 30miles/hour distance = 15miles

Time taken = distance / speed

= 30/15= 2 hours

The total distance traveled to three places is = 15+ 15+15= 45miles

The Total time taken is = 0.6+ 2.67+ 2= 5.267=5.3 hours

Speed = Total Distance / Total Time

Speed= 45/ 5.3

= 8.49=8.5 miles per hour

The average speed of the entire trip is 8.5 miles per hour.

7 0

3 years ago