The second term would be -3f^3 because when in descending order it is
6f^4 - 3f^3 - 2f^2 + 9f
The answer is a.0.32 km.
The speed that a tsunami can travel is modeled by the equation is s = 356√d.
It is given:
s = 200 km/h
d = ?
Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562
Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32
Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
The only two dice you can roll and multiply to get 30 are a five and a six. Thus, you get
Answer:
5280*13 = 16640
Step-by-step explanation:
5280*13 =
5280
* 13
-----------
52800
+ 15840
-------------
16640
