Hi! So I got :
-3 —>20
-2 —>13
-1 —>8
0 —>5
1 —>4
2 —>5
3 —>8
I’m sorry if any of these are wrong but In order to find the answers I used the “graphing quadratics” one (don’t know the name so sorry) but yeah first I found the axis of symmetry which was 1 and from there I built a chart and substituted. Again, I didn’t see some answer choices above in the image so sorry if there wrong, but yeah I hope this helped! (This is from algebra 1 by the way)
hello :
<span>(-101)+102+(-103)+104+...+(-199)+200
=( </span>(-101)+(-103) +....+ (-199) ) +( (102) + ( 104) +....+(200))
let : A = ( (-101)+(-103) +....+ (-199) )
B = ( (102) + ( 104) +....+(200))
note : the sum n term of arithemtic sequence
S= n/2(u1 + un)
un = u1 +(n-1) d u1 : the first term d : the common diference
in A : u1= -101 d = -2 n = 49...
in B : u1 =102 d=2 n= 49
A = 49/2(-101-199) =-7350
B=49/2(102+200)=4949
(-101)+102+(-103)+104+...+(-199)+200 = A+B =-2401
Answer:
1.25
Step-by-step explanation:
Answer:
10.8 meters
Step-by-step explanation:
This situation forms a right triangle, where the length of the kite string is the hypotenuse, the distance from where it is held is the long leg, and the height is the short leg.
Use the pythagorean theorem to solve for c, the length of the kite string.
a² + b² = c²
6² + 9² = c²
36 + 81 = c²
117 = c²
10.8 = c
So, the length of the kite string is 10.8 meters
