What line shows the first error in the solution?

Hi! Does any one know how to do proportions? If so can you please help me out with these 2 problems? please show work on how you

Nataly [62]

Answers:

1.) 18 lemons
2.) 80 minutes

Explanation:

Porportions are a lot like fractions. For the first question, you can make the fraction 6/8, or 3/4 simplified. This means that for every 8 cups of water, you need 6 lemons.

Then, to find the amount of lemons you need if you have 24 cups of water, you need to think about what×8= 24. If we divide 24 by 8, we get 3, so if we multiply our fraction by 3/3, we should get the answer.

If we do 6/8 × 3/3, we get 18/24. This means that we need 18 lemons if we were to use 24 cups of water.

For the next question, our fraction 15/60, for 15 cakes baked in 60 minutes. Now we need to divide 20 cakes by 15.

This question is a little different from the first one because there will be a decimal involved. If we do 20/15, we get 1⅓. This means that this time, we will multiply 15/60 by (1⅓)/(1⅓).

If we multiply 60 by 1⅓, we get 80, which is the number of minutes needed to bake 20 cakes.

Hope this helps :)

6 0

3 years ago

Write log4 14 as a logarithm of base 3. <br><br> HELP!!!!!

Sonja [21]

It would be log3 14/log3 4
Hope this helps. (:

3 0

2 years ago

Read 2 more answers

coppers mother gives him $79 to the store, he buys 15 loaves of bread and 28 cartons of juice each bread is $3 and each juice ca

Leviafan [203]

He doesn't have a positive number. Add $45 and $112 together and it exceeds $79

3 0

2 years ago

Read 2 more answers

Last month a museum received €21000 in donations.After taking off the cost of monthly bills,,the museum spent the remaining mone

Rainbow [258]

Answer:

$13,500.

Step-by-step explanation:

Let x represent money spent on monthly bills.

We have been given that last month a museum received €21000 in donations. The ratio of bills to donations was 5:14.

We will use proportions to solve our given problem.

$\frac{\text{Bills}}{\text{Donations}}=\frac{5}{14}$

$\frac{x}{21000}=\frac{5}{14}$

$\frac{x}{21000}*21000=\frac{5}{14}*21000$

$x=5*1500$

$x=7500$

Now, we will subtract $7500 from donations to find the amount spent on new exhibitions as:

$\$21,000-\$7500=\$13,500$

Therefore, they spent $13,500 on new exhibitions.

6 0

2 years ago

A rectangle has a length 6 more than it's width if the width is decreased by 2 and the length decreased by 4 the resulting has a

Rashid [163]

Answer:

Length of original rectangle: 11 units.

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

$\text{Perimeter of new rectangle}=20$

Step-by-step explanation:

Let x represent width of the original rectangle.

We have been given that a rectangle has a length 6 more than it's width. S the length of the original rectangle would be $x+6$ .

We have been given that when the width is decreased by 2 and the length decreased by 4 the resulting has an area of 21 square units.

The width of new rectangle would be $x-2$ .

The length of new rectangle would be $x+6-4=x+2$ .

The area of new rectangle would be $(x+2)(x-2)$ .

Now we will equate area of new rectangle with 21 and solve for x as:

$(x+2)(x-2)=21$

Applying difference of squares, we will get:

$x^2-2^2=21$

$x^2-4=21$

$x^2-4+4=21+4$

$x^2=25$

Since width cannot be negative, so we will take positive square root of both sides.

$\sqrt{x^2}=\sqrt{25}$

$x=5$

Therefore, the width of original rectangle is 5 units.

Length of the original rectangle would be $x+6\Rightarrow x+5=11$ .

Therefore, the length of original rectangle is 11 units.

$\text{Area of original rectangle}=5\times 11$

$\text{Area of original rectangle}=55$

Therefore, area of the original rectangle is 55 square units.

Now we will find ratio of the original rectangle area to the new rectangle area as:

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

We know that perimeter of rectangle is two times the sum of length and width.

$\text{Perimeter of new rectangle}=2((x+2)+(x-2))$

$\text{Perimeter of new rectangle}=2((5+2)+(5-2))$

$\text{Perimeter of new rectangle}=2(7+3)$

$\text{Perimeter of new rectangle}=2(10)$

$\text{Perimeter of new rectangle}=20$

Therefore, the perimeter of the new rectangle is 20 units.

7 0

3 years ago