Which transformations will produce similar, but not congruent, figures?

1 answer:

6 0

The correct answer is A. Triangle TUV is dilated by a scale factor of 9 and then translated 2 units right and 1 unit down to form triangle TꞌꞌUꞌꞌVꞌꞌ.

Congruent figures are of the same shape and the same size. Triangle TUV is dilated by a scale factor of 9 and then translated 2 units right and 1 unit down to form triangle TꞌꞌUꞌꞌVꞌꞌ will produce similar but not congruent figures because they have different sizes.

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The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

8 0

2 years ago

Z - 12 = 6 A. 10 B. 15 C. 18 D. 6 Need help working it out

const2013 [10]

Z-12=6

you take the 12 and add it to both sides making it look like:
z-12+12=6+12
which also looks like
z-0=6+12

z-0 = z

so now you have
z=6+12

6+12 = 18

SO Z=18!!!

your answer is 18

8 0

1 year ago

Read 2 more answers

NEED HELP ASAP THANKS

Oxana [17]

1/4w+4 - 1/2w+3
-1/4+7

4 0

2 years ago

I will give you branilest!

Yanka [14]

About 455 days

hope this helped

6 0