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3 years ago

I dont understand how to do the 2x part.

Mathematics

1 answer:

kodGreya [7K]3 years ago

4 0

Answer:

x=6 2/3

Step-by-step explanation:

Ratio of DEF:ABC=5/3

8*5/3=13 1/3

x=6 2/3

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What is the y-intercept of y=3x-2/3

Gre4nikov [31]

Answer: -2/3

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3 years ago

A central angle of a circle measures 1.5 radians. If the radius of the circle is 3 cm, what is the area of the related sector?

soldi70 [24.7K]

Answer:

Option B. $6.75\ cm^{2}$

Step-by-step explanation:

we know that

The area of a circle is equal to

$A=\pi r^{2}$

we have

$r=3\ cm$

substitute

$A=\pi (3^{2})=9 \pi\ cm^{2}$

Remember that

$2\pi$ radians subtends the complete circle of area $9 \pi\ cm^{2}$

by proportion

Find the area of the related sector for a central angle of $1.5$ radians

Let

x------> the area of the related sector

$\frac{9 \pi}{2\pi}\frac{cm^{2}}{radians} =\frac{x}{1.5}\frac{cm^{2}}{radians}\\ \\x=9*1.5/2\\ \\x= 6.75\ cm^{2}$

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3 years ago

A rock is thrown upward with a velocity of 12 meters per second from the top of a 34 meter high diff, and it moloses the diff on

zalisa [80]

It is 10.5 because it is

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3 years ago

A student has a test grade of 85%. If the student does extra problems and his grade raises by 15% of the test, what would be the

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Yes he is receiving a perfect score now
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3 years ago

Find the coordinates of the point three tenths<br><br> of the way from A(-4, -8) to B(11, 7)

Leviafan [203]

let's first off take a peek at those values.

let's say the point with those coordinates is point C, so C is 3/10 of the way from A to B.

meaning, we take the segment AB and cut it in 10 equal pieces, AC takes 3 pieces, and CB takes 7 pieces, namely AC and CB are at a 3:7 ratio.

$\bf ~~~~~~~~~~~~\textit{internal division of a line segment}
\\\\\\
A(-4,-8)\qquad B(11,7)\qquad
\qquad \stackrel{\textit{ratio from A to B}}{3:7}
\\\\\\
\cfrac{A\underline{C}}{\underline{C} B} = \cfrac{3}{7}\implies \cfrac{A}{B} = \cfrac{3}{7}\implies 7A=3B\implies 7(-4,-8)=3(11,7)\\\\[-0.35em]
~\dotfill\\\\
C=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em]
~\dotfill$

$\bf C=\left(\cfrac{(7\cdot -4)+(3\cdot 11)}{3+7}\quad ,\quad \cfrac{(7\cdot -8)+(3\cdot 7)}{3+7}\right)
\\\\\\
C=\left( \cfrac{-28+33}{10}~~,~~\cfrac{-56+21}{10} \right)\implies C=\left( \cfrac{5}{10}~~,~~\cfrac{-35}{10} \right)
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
~\hfill C=\left( \frac{1}{2}~,~-\frac{7}{2} \right)~\hfill$

4 0

3 years ago