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3 years ago

Is this a function? Yes or No

Mathematics

2 answers:

Oliga [24]3 years ago

8 0

No, the output has more than one input

tester [92]3 years ago

4 0

Answer:

Step-by-step explanation:

Because the number 4 repeats itself in a function no numbers repeat themselves

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Let a is in {−3, −1, 0}. Evaluate −a for each element of the set.

12345 [234]

Ok so a∈{-3,-1,0}. then just {-3*-1,-1*-1,0*-1} which comes to {3,1,0}

7 0

3 years ago

20. Which of the following conditions must hold in the equilibrium of a competitive market where the government puts a specific

Nuetrik [128]

Answer: A

Step-by-step explanation:

6 0

3 years ago

Elena bikes 20 minutes each day for exercise. Write an equation to describe the relationship between her distance in miles, D, a

nika2105 [10]

Answer:

<h2>D= 3.9 miles</h2>

Step-by-step explanation:

Given data

speed v= 13 miles per hour

time taken t= 20min to hour 0.3 hours

the distance D

We know that the relationship between speed, time, and distance

speed=distance/time

13=D/0.3

(the expression above describes the relationship between distance, speed, and time)

making D subject of formula we have

D= 0.3*13

D= 3.9 miles

hence the distance is 3.9miles

6 0

3 years ago

1. x + 2x - 1 = 38<br> Inverse operation

Lena [83]

Answer:

x=13

Step-by-step explanation:

First, you add the x's together: 2x+x=3x

Now you have:3x-1=38

Add 1 to both sides: 3x=39

1 cancel on the left side of the equation

Divide 3 on both sides: x=39/3

3 cancels on the left side and 39 divided by 3 is 13:

x=13

Hope this helps!

6 0

3 years ago

Please help!

777dan777 [17]

Answer:

$\begin{array}{ccc}\text{Radius}&\text{Volume of sphere}&\text{Volume of cylinder}\\&&\\1&\dfrac{4}{3}\pi &2\pi \\&&\\2&\dfrac{32}{3}\pi &16\pi \\&&\\3&36\pi &54\pi \\&&\\4&\dfrac{256}{3}\pi &128\pi \\&&\\5&\dfrac{500}{3}\pi &250\pi\end{array}$

Step-by-step explanation:

Use formulas for the volumes:

$V_{sphere}=\dfrac{4}{3}\pi r^3,\\ \\V_{cylinder}=\pi r^2h=\pi r^2\cdot 2r=2\pi r^3.$

1. When r=1,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 1^3=\dfrac{4}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 1^3=2\pi.$

2. When r=2,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 2^3=\dfrac{32}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 2^3=16\pi.$

3. When r=3,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 3^3=36\pi,\\ \\V_{cylinder}=2\pi \cdot 3^3=54\pi.$

4. When r=4,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 4^3=\dfrac{256}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 4^3=128\pi.$

5. When r=5,

$V_{sphere}=\dfrac{4}{3}\pi\cdot 5^3=\dfrac{500}{3}\pi,\\ \\V_{cylinder}=2\pi \cdot 5^3=250\pi.$

Note that for all r,

$\dfrac{V_{sphere}}{V_{cylinder}}=\dfrac{\frac{4}{3}\pi r^3}{2\pi r^3}=\dfrac{2}{3}.$

8 0

3 years ago

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