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3 years ago

Use completing the square to solve for x in the equation (x-12)(x+4)=9

Mathematics

2 answers:

IrinaVladis [17]3 years ago

8 0

Move all terms to the left side and set equal to zero. then set the factors equal to 0 x = 13,3

Citrus2011 [14]3 years ago

8 0

(x-12)(x+4)=9
+12 -4 +8
(x)(x)=17
x^2=17
x=1 or 7

Can I get brainliest please?

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Solve the equation for all values of x. ∣4x + 4 ∣- 10 = 3x

sertanlavr [38]

Answer:

X = 6 , – 2

Step-by-step explanation:

| 4x +4| - 10 =3x

4x +4 - 10 = 3x

4x - 3x = 10 - 4

x = 6

_____o___o____

– (4x + 4) – 10 = 3x

– 4x – 4 – 10 = 3x

3x + 4x = – 4 – 10

7x = – 14

x = – 14/ 7

x = – 2

I hope I helped you^_^

6 0

3 years ago

Please do your best to give me the correct answer! thank you so much! :)

Nataliya [291]

Answer: m= -1/8

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6 0

3 years ago

What is the measure of arc EF in circle H? O 41° O 50° O 114 O 1730

timurjin [86]

Answer:

The measure of arc EF = 41°

Step-by-step explanation:

Given:

Arc DE = 73°

$\angle FED=123\°$

Now, we know from central angle theorem that the measure of central angle by an arc is twice that of the angle made by the same arc at the circumference. Therefore,

$\textrm{Major Arc DGF}=2\times \angle FED\\\textrm{Major Arc DGF}=2\times 123\\\textrm{Major Arc DGF}=246\°$

Now, we know that sum of all arcs on a circle is equal to 360°.

Therefore, arc DGF + arc DE + arc EF = 360°

$246+73+arc\ EF=360\\319+arc\ EF=360\\arc\ EF=360-319=41\°$

Therefore, the measure of the arc EF is 41°.

7 0

4 years ago

Read 2 more answers

Simplify: cos2x-cos4 all over sin2x + sin 4x

GrogVix [38]

Answer:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

Step-by-step explanation:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}$

Apply formula:

$\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$ and

$\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$

We get:

$=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}$

$=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}$

$=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}$

$=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}$

$=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}$

$=\frac{\sin\left(x\right)}{\cos\left(x\right)}$

$=\tan\left(x\right)$

Hence final answer is

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

6 0

3 years ago

What is the solution to (x+6)(x+2)=60

Citrus2011 [14]

Distribute to eliminate the parenthesis

x^2 + 2x + 6x + 12 = 60

Combine like terms

x^2 + 8x + 12 = 60

Subtract 60 from both sides

x^2 + 8x - 48 = 0

Factor the equation

(x+12)(x-4)=0
x+12=0
x+4=0

x= -12 and -4

5 0

4 years ago