1. Open the compass to a little more than halfway across the line segment XY. Draw an arc centered at the first endpoint X across the line segment XY. Without changing the width of the compass, place the compass tip on the
second endpoint Y. Draw a second arc across the line segment XY.
2. Line up a straightedge with the intersection of the arcs above the line XY,
and the intersection of the arcs below the line. Draw a line connecting
these two points. The line you draw is a perpendicular bisector. It
bisects the line XY at a right angle.
3. Use a compass and straightedge to construct the bisectors of the line YZ as you did with the first line segment. Extend the bisectors long enough that they intersect. The point of their intersection is the center of the circle.
4. The radius of a circle is the distance from the center to any point on the circle’s edge.
To set the width, place the tip of the compass on the center of the
circle, and open the compass to any one of your original points.Swing the compass around 360 degrees so that it draws a complete circle. The circle should pass through all three points.
Your answer should be 31
Tell me if it was correct?
Thanks!
The perimeter is 1/2 the perimeter of ABCD because the scale factor is 1/2. It would be 10 units.
Let the radius of the circle be r. Then the line from the external point through the center of the circle which extends to the far point on the circle has length 3r .By the tangent - secant theorem
t^2 = 3r * r = 3r^2 ( where t is the length of the tangent).
So t = √(3r^2) = √3r answer.
